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shtirl [24]
3 years ago
7

Given that p=9i+12j and q=-6i-8j. Evaluate |p-q|-{|p|-|q|}

Mathematics
1 answer:
krok68 [10]3 years ago
7 0

Answer:

|p-q|-(|p|-|q|) = 20

Step-by-step explanation:

First let's find the value of 'p-q':

p - q = 9i + 12j - (-6i - 8j)\\p - q = 9i + 12j + 6i + 8j\\p - q = 15i + 20j\\

To find |p-q| (module of 'p-q'), we can use the formula:

|ai + bj| = \sqrt{a^{2}+b^{2}}

Where 'a' is the coefficient of 'i' and 'b' is the coefficient of 'j'

So we have:

|p - q| = |15i + 20j| = \sqrt{15^{2}+20^{2}} = 25

Now, we need to find the module of p and the module of q:|p| = |9i + 12j| = \sqrt{9^{2}+12^{2}} = 15

|q| = |-6i - 8j| = \sqrt{(-6)^{2}+(-8)^{2}} = 10

Then, evaluating |p-q|-{|p|-|q|}, we have:

|p-q|-(|p|-|q|) = 25 - (15 - 10) = 25 - 5 = 20

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Given that |-6| > 5, which statement is not true?
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tester [92]

Part A: x = -5/4, 3 || (-5/4, 0) (3, 0)

To find the x-intercepts, we need to know where y is equal to 0. So, we will set the function equal to 0 and solve for x.

4x^2 - 7x - 15 = 0

4 x 15 = 60 || -12 x 5 = 60 || -12 + 5 = -7

4x^2 - 12x + 5x - 15 = 0

4x(x - 3) + 5(x - 3) = 0

(4x + 5)(x - 3) = 0

4x + 5 = 0

x = -5/4

x - 3 = 0

x = 3

Part B: minimum, (7/8, -289/16)

The vertex of the graph will be a minimum. This is because the parabola is positive, meaning that it opens to the top.

To find the coordinates of the parabola, we start with the x-coordinate. The x-coordinate can be found using the equation -b/2a.

b = -7

a = 4

x = -(-7) / 2(4) = 7/8

Now that we know the x-value, we can plug it into the function and solve for the y-value.

y = 4(7/8)^2 - 7(7/8) - 15

y = 4(49/64) - 49/8 - 15

y = 196/64 - 392/64 - 960/64

y = -1156/64 = -289/16 = -18 1/16

Part C:

First, start by graphing the vertex. Then, use the x-intercepts and graph those. At this point we should have three points in a sort of triangle shape. If we did it right, each of the x-values will be an equal distance from the vertex. After we have those points graphed, it is time to draw in the parabola. Knowing that the parabola is positive, we draw in a U shape that passes through each of the three points and opens toward the top of the coordinate grid.

Hope this helps!

6 0
2 years ago
-6x-7=3x+11 how to solve this problem
Shalnov [3]
You have to get the x to one side so you'll subtract 3x from -6x and 3x from 3x, the 3x will cancel out and -6x - 3x is -9x-7=11, you have to add 7 from both sides the 7+7 cancels out  and also add 11+7 which leaves -9x=18, you have to divide -9x/-9 and do 18/-9, which gets you x=-2. Here's the work shown if you didn't what i said...
-6x-7=3x+11
-3x    -3x
-9x-7=11
    +7  +7
-9x=18
-9   -9
x=-2
6 0
3 years ago
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