3 years ago

I need help with this question!

Mathematics

1 answer:

stepladder [879]3 years ago

8 0

F(x)=2x^4 is the answer

You might be interested in

In AHIJ, the measure of J=90°, IJ = 5 feet, and JH = 3.2 feet. Find the measure of

Virty [35]

Answer:33.6

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

27x +13 +12y - 3 x 17x - simplify this

noname [10]

Answer to this question is
12 ( 2x + y) + 13

6 0

4 years ago

Write an expression with five different terms that is equivalent to 8x^2 + 3x^2 + 3y

Misha Larkins [42]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

An expression having five terms which is equivalent to above term is :

$5x {}^{2} + 3 {x}^{2} + 3{x}^{2} +4y - y$

3 0

3 years ago

Do anyone know <br> -8(1+4x)+7x=-25-8x

bulgar [2K]

Answer:

x = 1

Step-by-step explanation:

-8(1+4x)+7x=-25-8x (Given)

-8 + -32x + 7x = -25 - 8x (Distribute)\

-8 + -25x = -25 - 8x (Combine like terms)

-17x = -17 (Move variables(x) to the left and constants to the right)

x = 1 (Divide) (the answer is positive because when you divide a negative number by a negative number it turns positive)

8 0

2 years ago

Read 2 more answers

Find two positive numbers satisfying the given requirements. The product is 216 and the sum is a minimum. (No Response) (smaller

fgiga [73]

Answer:

$x1=\sqrt{216} \ and \ y1=\ \sqrt{216}$

Step-by-step explanation:

Let the first number is x1 and other number is y1 then

$x1 * y1 =216$

Therefore

$y1=$ $\frac{216}{x1}$

also there sum is

$s1 =x1+y1$ ....Eq(1)

Putting the value of y1 in the previous equation

$s1\ =x1 + \frac{216}{x1}$ ........Eq(2)

Differentiate the the Eq(2) with respect to x1 we get

$\frac{ds1}{dx1} \ =\ 1+216*\frac{1}{-x1^{2} }$

$\frac{ds1}{dx1} \ =\ 1-\frac{216}{x1^{2} }\ =\ 0$

${x1^{2} }\ =\ 216\\ x1=\sqrt{216}$

Putting the value of X1 in Eq(1) we get

$y1=\frac{216}{\sqrt{216} } \\y1=\frac{216*\sqrt{216} }{216} \\y1=\ \sqrt{216}$

So $x1=\sqrt{216} \ and \ y1=\ \sqrt{216}$

6 0

4 years ago