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Svet_ta [14]
3 years ago
7

Could someone pls help me

Mathematics
1 answer:
Rom4ik [11]3 years ago
8 0

Answer: Ik an easier way to answer it without waiting for someone to answer it for you. So all you have to do is search up the question for each expression and you'll find it. I remember doing this yesterday for nearly that exact worksheet but i forget the answers and cant go back so im just telling you how to find the answers your welcome

Step-by-step explanation:

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Trevin puts 8 gallons of gas in his car and pays $22 What was the cost of 1 gallon of gas
castortr0y [4]

Answer:

2.75

Step-by-step expl

6 0
3 years ago
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$x$ $4$ $1$ <br> $10$<br> $y$ $10$
ivanzaharov [21]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The ratios in the table must be equivalent if it is to be filled in with something other than random numbers.

__

The second row is 10/4 = 2.5 times the first.

The first row is 4/10 = 0.4 times the second.

4 0
3 years ago
I really need help with this one please
natka813 [3]

The distance from the sun is option 2 5.59 astronomical units.

Step-by-step explanation:

Step 1; To solve the question we need two variables. P which represents the number of years a planet takes to complete a revolution around the Sun. This is given as 13.2 years in the question so P = 13.2 years. The other variable is the distance between the planet and the sun in astronomical units. We need to determine the value of this using the given equation.

Step 2; So we have to calculate the value of 'a' in Kepler's equation. But the exponential power \frac{3}{2} is on the variable we need to find so we multiply both the sides by an exponential power of \frac{2}{3} to be able to calculate 'a'.

P =  a^{\frac{3}{2} }, P^{\frac{2}{3} } = a^{\frac{3}{2}*\frac{2}{3}  },  P^{\frac{2}{3} } = a, 13.2^{\frac{2}{3} } = a = 5.58533 astronomical units.

Rounding it over to nearest hundredth we get 5.59 astronomical units.

6 0
4 years ago
You and a friend play a game where you each toss a balanced coin. If the upper faces on the coins are both tails, you win $1; if
oksian1 [2.3K]

Answer:  The mean and variance of Y is $0.25 and $6.19 respectively.

Step-by-step explanation:

Given : You and a friend play a game where you each toss a balanced coin.

sample space for tossing two coins : {TT, HT, TH, HH}

Let Y denotes the  winnings on a single play of the game.

You win $1; if the faces are both heads

then P(Y=1)=P(TT)=\dfrac{1}{4}=0.25

You win $6; if the faces are both heads

then P(Y=6)=P(HH)=\dfrac{1}{4}=0.25

You loose $3; if the faces do not match.

then P(Y=1)=P(TH, HT)=\dfrac{2}{4}=0.50

The expected value to win : E(Y)=\sum_{i=1}^{i=3} y_ip(y_1)

=1\times0.25+6\times0.25+(-3)\times0.50=0.25

Hence, the mean of Y : E(Y)= $0.25

E(Y^2)=\sum_{i=1}^{i=3} y_i^2p(y_i)\\\\=1^2\times0.25+6^1\times0.25+(-3)^2\times0.5\\\\=0.25+1.5+4.5=6.25

Variance = E[Y^2]-E(Y)^2

=6.25-(0.25)^2=6.25-0.0625=6.1875\approx6.19

Hence, variance of Y = $ 6.19

6 0
4 years ago
A square piece of confetti has a perimeter of 28 millimeters. How long is each side of the piece of confetti?
ch4aika [34]
7 is the answer for each side


5 0
4 years ago
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