9514 1404 393
Answer:
see attached
Step-by-step explanation:
The ratios in the table must be equivalent if it is to be filled in with something other than random numbers.
__
The second row is 10/4 = 2.5 times the first.
The first row is 4/10 = 0.4 times the second.
The distance from the sun is option 2 5.59 astronomical units.
Step-by-step explanation:
Step 1; To solve the question we need two variables. P which represents the number of years a planet takes to complete a revolution around the Sun. This is given as 13.2 years in the question so P = 13.2 years. The other variable is the distance between the planet and the sun in astronomical units. We need to determine the value of this using the given equation.
Step 2; So we have to calculate the value of 'a' in Kepler's equation. But the exponential power
is on the variable we need to find so we multiply both the sides by an exponential power of
to be able to calculate 'a'.
P =
,
=
,
= a,
= a = 5.58533 astronomical units.
Rounding it over to nearest hundredth we get 5.59 astronomical units.
Answer: The mean and variance of Y is $0.25 and $6.19 respectively.
Step-by-step explanation:
Given : You and a friend play a game where you each toss a balanced coin.
sample space for tossing two coins : {TT, HT, TH, HH}
Let Y denotes the winnings on a single play of the game.
You win $1; if the faces are both heads
then P(Y=1)=P(TT)=
You win $6; if the faces are both heads
then P(Y=6)=P(HH)=
You loose $3; if the faces do not match.
then P(Y=1)=P(TH, HT)=
The expected value to win : E(Y)=

Hence, the mean of Y : E(Y)= $0.25

Variance = ![E[Y^2]-E(Y)^2](https://tex.z-dn.net/?f=E%5BY%5E2%5D-E%28Y%29%5E2)

Hence, variance of Y = $ 6.19