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Svet_ta [14]
3 years ago
7

Could someone pls help me

Mathematics
1 answer:
Rom4ik [11]3 years ago
8 0

Answer: Ik an easier way to answer it without waiting for someone to answer it for you. So all you have to do is search up the question for each expression and you'll find it. I remember doing this yesterday for nearly that exact worksheet but i forget the answers and cant go back so im just telling you how to find the answers your welcome

Step-by-step explanation:

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The following table shows the number of classes that
Tresset [83]

Answer:

There are 6 classes we find the median by finding the middle number of the 3rd highest class and 4th highest class, even if this is a decimal.

6/3 = 3+ 0.5

The process would be different if some values are the same values already on the chart total of each class.

ie) 20  31  14  22 20 31

small data like this below you can rearrange

14  20  20  22  31 31  

and see that 21 is the correct value

as there are even numbers, so we choose 20 , 22

and select the middle value = 21

Step-by-step explanation:

If there is an even number of numbers locate the two middle numbers so that there is an equal number of values to the left and to the right of these two numbers. Step 3: If there is an odd number of numbers, this middle number is the median. If there is an even number of numbers add the two middles and divide by 2.

7 0
3 years ago
The altitude of an equilateral triangle is 9 inches. Find the perimeter of the triangle in inches.
Fiesta28 [93]
If we  draw a perpendicular line from one of the vertices of the triangle we get  2 right angled triangles  each with  altitude 9 ins  and vertex angle = 30 degrees.   So:-

cos 30 = 9 /h     where h = one of the sides of the equilateral triangle

h =  9 / cos 30  =  10.392 inches

Therefore the perimeter of the triangle = 3 * 10.392 =  31.1769 ins

Answer is 31.18 inches to the nearest hundredth.
5 0
3 years ago
9. Sarah has to create a floral arrangement out of twigs and flowers that has a total of 9 objects. She has to
noname [10]

Answer:

tu debes de saber por qué si yo lo sé tú también no es verdad

6 0
3 years ago
I need help quick!!!
babunello [35]
Are you needing help with the last box or what are u needing help with ?
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3 years ago
If a point is equidistant from the endpoint of segment, then it is
Mashutka [201]

Hi

.... then it is  located on the perpendicular bisector.

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