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Ket [755]
4 years ago
6

What would 2x + 3y = 1,470 be in slope intercept form and how do you get it

Mathematics
2 answers:
Flauer [41]4 years ago
6 0

slope intercept formula is y = mx + b.

Isolate the y. Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS. First, subtract 2x from both sides

2x (-2x) + 3y = (-2x) + 1470

3y = -2x + 1470

Isolate the y. Divide 3 from both sides

(3y)/3 = (-2x + 1470)/3

y = (-2x + 1470)/3

Simplify

y = (-2/3)x + 490

y = (-2/3)x + 490 is your answer

hope this helps

Artist 52 [7]4 years ago
3 0
  • Slope-Intercept Form: y = mx + b, with m = slope and b = y-intercept.

So firstly, subtract 2x on both sides of the equation: 3y=-2x+1470

Next, divide both sides by 3 and <u>your final answer will be y=-\frac{2}{3}x+490</u>

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8 0
3 years ago
How do I solve this?
serg [7]

Answer:

  (x, y) = (18, 5)

Step-by-step explanation:

Assuming the three lines meet at a single point at lower left (the figure is sloppily drawn), the angle (3x)°+49° is a corresponding angle to (7x-23)°. That means they have the same measure:

  3x +49 = 7x -23

  72 = 4x . . . . . . . . . add 23-3x

  18 = x . . . . . . . . . . . divide by 4

__

Angles (3x)° and (11y-1)° are "corresponding" angles, so are congruent.

  3x = 11y -1

  3(18) +1 = 11y . . . . add 1, fill in the value of x

  55/11 = y = 5 . . . . divide by 11

The values of x and y are 18 and 5, respectively.

5 0
4 years ago
Which statement is true for the equation 3x − 3x − 2 = −2?
Mariana [72]
Has infinitely many solutions. 
3 0
3 years ago
Read 2 more answers
What would the class size be if 30 people represent 40% of the class?
anastassius [24]

Answer:

110 students

Step-by-step explanation:

%40 Divide 30

30 divided by %40 is 0.75

SO there is 60% left

%60 divided by 0.75

That is 80

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6 0
3 years ago
Please find the value of X and Y will mark brainliest
MAVERICK [17]

Answer:

y=34.5 degrees

x=17 degrees

Step-by-step explanation:

2y=69  because it is a corresponding congruent angle

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7 0
3 years ago
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