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MakcuM [25]
4 years ago
5

If you roll one die and flip one coin, does the occurrence of a particular outcome on the die affect the probability of a partic

ular outcome on the coin? Why or why not?
Mathematics
1 answer:
EastWind [94]4 years ago
4 0

Answer:

No, because these events are independent.

Step-by-step explanation:

When we roll one die (a fair die), we will have outcomes in the numbers from 1 to 6.

And when we flip a coin, we will have either a heads or a tails.

Now these two events are independent events as the occurrence of any result in one event is not affecting the result of second event,

Hence, these two are independent events. <em>So, the answer is no, the occurrence of a particular outcome on the die will not affect the probability of a particular outcome on the coin.</em>

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Justine and Meagan played a trivia game. Justine answered a question incorrectly and lost 7 points. Then Meagan answered correct
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Answer:

The correct way to represent that "the opposite of Justine's score was equal to Meagan's score" is [- (-7)].

Step-by-step explanation:

We know that the opposite of the opposite of a number, say 2, is the number itself.

That is:

Opposite of 2 is -2.

Then the opposite of -2 is:

- (-2) = 2

It is provided that:

  • Justine answered a question incorrectly and lost 7 points.
  • Then Meagan answered correctly and got the opposite score.

Assume that both Justine and Meagan started with 0 score.

Justine plays first.

If Justine answered a question incorrectly, his score would be -7.

Then Meagan plays, and answers the question correctly.

So, Meagan got the opposite score.

The opposite of -7 will be [- (-7)].

Thus, the correct way to represent that "the opposite of Justine's score was equal to Meagan's score" is [- (-7)].

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3 years ago
In the above bridge, line segment BD is the perpendicular bisector of line segment AC. For the bridge to be safe, Triangle ABD i
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Answer: SAS postulate will be use to prove  Δ ABD ≅ ΔCBD

Step-by-step explanation:

Here, In ΔABC line segment BD is the perpendicular bisector of line segment AC,

Therefore, BD ⊥ AC and, AD=DC

Thus, In triangles ABD and CBD,

AD≅DC     ( given)

∠ADB≅∠CDB ( Right angles)

BD≅BD            ( Reflexive)

Therefore, By SAS postulate of congruence,

Δ ABD ≅ ΔCBD.





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Step-by-step explanation:

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Perfect square, yes. Perfect cube, no.

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