<span>E[Y] = 0.4·1 + 0.3·2 + 0.2·3 + 0.1·4 = 2
E[1/Y] =0.4·1/1 + 0.3·1/2 + 0.2·1/3 + 0.1·1/4 = 0.4 + 0.15 + 0.0666 + 0.025?0.64
V[Y] =E[Y2]-E[Y]2= (0.4)·12+(0.3)·22+(0.2)·32+(0.1)·42-22= 0.4+1.2+1.8+1.6-4= 5-4 = 1</span>
> your welcome :) and tell me if it’s right
Yes this is equal because 3v+v is 4v and if you divide 12v by 3 you also get 4v
Answer:
n<2
Step-by-step explanation:
move all terms not containing n to the right side of the inequality