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Vanyuwa [196]
3 years ago
5

Plz help and no spam plz. A large university accepts 60% of the students who apply. Of the students the

Mathematics
2 answers:
mihalych1998 [28]3 years ago
3 0
2,600 students actually enroll.
mylen [45]3 years ago
3 0

Answer:

2100

Step-by-step explanation:

60%=0.6

35%=0.35

0.6*0.35=0.21

0.21*10000=2100

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kari74 [83]
6506 or 656 is the answer
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7x(3x2) and (7x3)x2​
Elis [28]

Answer:

what is the question

Step-by-step explanation:

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3 years ago
I need help with the top 3 plz
attashe74 [19]

Answer/Step-by-step explanation:

Recall: SOHCAHTOA

1. Reference angle = 70°

Adjacent side = x

Hypotenuse = 6 cm

Apply CAH. Thus,

Cos 70 = adj/hyp

Cos 70 = x/6

6 × cos 70 = x

2.05 = x

x = 2.05 cm

2. Reference angle = 45°

Adjacent side = x

Hypotenuse = 1.3 m

Applying CAH, we would have the following ratio:

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Cos 45 = x/1.3

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3. The who diagram is not shown well. Some parts are missing, however you can still solve the problem just the same way we solved problem 1 and 2.

6 0
3 years ago
Find the measures of the numbered angles in each rhombus. So find 1 2 and 3
lakkis [162]

Answer:

1) 120

2) 30

3) 30

Step-by-step explanation:

Angle 1 is the same as the angle shown at 120

Use that to find 2, which is also 3

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6 0
3 years ago
The probability that you roll a 3 on a six-sided die is . The probability that you flip a coin that lands on tails is . The prob
aivan3 [116]

Answer:

1/6; 1/2; 1/12; P(T|3) = 1/2; therefore, events are independent because P(T|3) = P(T).

Step-by-step explanation:

The probability of rolling a 3 on a six-sided die is 1/6.  This is because there is one 3 out of 6 possibilities.

The probability of flipping a coin on tails is 1/2.  This is because there is one side "tails" out of 2 possibilities.

The probability of rolling a 3 and flipping tails is 1/6(1/2) = 1/12.

P(T|3) = P(3 and Tails)/P(3) = 1/12 / (1/6) = 1/12(6/1) = 6/12 = 1/2

Since P(T|3) = P(3), these are independent events.

3 0
3 years ago
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