Answer:
35/72
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Here, we want to find an equation in the options which is same as the equation given in the question;
The equation we are testing against is;
0.05n + 0.1d = 3.65
What we can do here is divide through by 0.01
So we will have;
0.05n/0.01 + 0.1d/0.01 = 3.65/0.01
= 5n + 10d = 365
Answer: C. ![\pi](https://tex.z-dn.net/?f=%5Cpi)
=======================================================
Explanation:
The x intercept always occurs when y = 0.
Use the unit circle to determine that
when ![\theta = \frac{\pi}{2} \text{ and } \theta = \frac{3\pi}{2}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Cfrac%7B%5Cpi%7D%7B2%7D%20%5Ctext%7B%20and%20%7D%20%5Ctheta%20%3D%20%5Cfrac%7B3%5Cpi%7D%7B2%7D)
So if
, then we have
![y = \cos\left(\frac{1}{2}x\right)\\\\y = \cos\left(\frac{x}{2}\right)\\\\y = \cos\left(\frac{\pi}{2}\right)\\\\y = 0\\\\](https://tex.z-dn.net/?f=y%20%3D%20%5Ccos%5Cleft%28%5Cfrac%7B1%7D%7B2%7Dx%5Cright%29%5C%5C%5C%5Cy%20%3D%20%5Ccos%5Cleft%28%5Cfrac%7Bx%7D%7B2%7D%5Cright%29%5C%5C%5C%5Cy%20%3D%20%5Ccos%5Cleft%28%5Cfrac%7B%5Cpi%7D%7B2%7D%5Cright%29%5C%5C%5C%5Cy%20%3D%200%5C%5C%5C%5C)
which shows us that
is the location of one of the infinitely many x intercepts for this function.
<h2>
Answer:</h2>
The probability is:
![\dfrac{1}{400}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B400%7D)
<h2>
Step-by-step explanation:</h2>
It is given that:
An urn contains balls numbered 1 through 20.
A ball is chosen, returned to the urn, and a second ball is chosen.
This means that this is a case of a replacement.
Hence, one of the event is independent of the other.
Now we know that the probability to get a particular number of ball is:
![\dfrac{1}{20}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B20%7D)
( Since, there are total 20 balls and a ball of one particular number is just unique )
i.e. ![\text{Probability of getting a 8}=\dfrac{1}{20}](https://tex.z-dn.net/?f=%5Ctext%7BProbability%20of%20getting%20a%208%7D%3D%5Cdfrac%7B1%7D%7B20%7D)
Hence, the probability that the first and second balls will be a 8 is:
![=\dfrac{1}{20}\times \dfrac{1}{20}\\\\\\=\dfrac{1}{400}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%7D%7B20%7D%5Ctimes%20%5Cdfrac%7B1%7D%7B20%7D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B400%7D)
Answer:
Correct option: ninth one.
m∠CQD = 22°
m∠EQF = 33°
Step-by-step explanation:
as the segment BQG is a straight line, its angle is 180 degrees, so the sum of all those 5 angles is equal to 180 degrees. So, we have that:
m∠FQG + m∠EQF + m∠DQE + m∠CQD + m∠BQC = 180°
12 + 3x + 103 + 2x + 10 = 180
5x + 125 = 180
5x = 55
x = 11°
Then, we have that:
m∠CQD = 2x = 22°
m∠EQF = 3x = 33°