Ask question

Ask question

All categories

konstantin123 [22]

4 years ago

14

He slope of the line that goes through (-3, -5$) and (-3,-6) is ____.

1 answer:

ryzh [129]4 years ago

4 0

Slope formula:

$\frac{y2-y1}{x2-x1}$

(-3, -5) (-3, -6)
x1 y1 x2 y2

so we just do
$\frac{-6 - (-5)}{-3 - (-3)}$

to get a slope of
$\frac{-1}{0}$

You might be interested in

In the figure below, AC is tangent to circle B. BA is a radius of circle B and A is a point of tangency. If AB is equal to 15 an

stich3 [128]

Using the pythagorean theorem
Base×Base + Perpendicular×Perpendicular = Hypotenuse× Hypotenuse
or B^2+P^2=H^2
B=root H^2 -P^2
Here hypotenuse =50 and Perpendicular = 15
therefore
root(50×50-15×15)
=root(2500-225)
=root(2275)
=47.69
=47.7 (approximately)
Option D is your answer.

3 0

3 years ago

Evaluate 25-5e+3/f when e=4 And f=3

VikaD [51]

The answer to your question is 6

8 0

3 years ago

Read 2 more answers

Multiple binomials by polynomials problem (2+3w)(w^2+6w+9)

muminat

Answer:

3w³ + 20w² + 39w + 18

Step-by-step explanation:

It is given that,

(2 + 3w)(w² + 6w + 9)

<u>To find the multiplication</u>

(2 + 3w)(w² + 6w + 9) = 2 * w² + 2 * 6w + 2* 9 + 3w * w² +3w * 6w + 3w* 9

= 2w² + 12w + 18 + 3w³ + 18w² + 27w

= 3w³ + 20w² + 39w + 18

Therefore the final value = 3w³ + 20w² + 39w + 18

5 0

3 years ago

Multiplying and dividing radical expressions and leaving them in factored form. I am trying to find the best and easy way to get

natka813 [3]

Answer:

$\frac{3x + 8}{36 - 2x} / \frac{27x^2 + 72x}{3x^2 - 27} = \frac{(x - 3)(x+3)}{6x(18 - x)}$

Step-by-step explanation:

Given

$\frac{3x + 8}{36 - 2x} / \frac{27x^2 + 72x}{3x^2 - 27}$

Required

Solve

Change / to *

$\frac{3x + 8}{36 - 2x} * \frac{3x^2 - 27}{27x^2 + 72x}$

Factor out 3

$\frac{3x + 8}{36 - 2x} * \frac{3(x^2 - 9)}{3(9x^2 + 24x)}$

$\frac{3x + 8}{36 - 2x} * \frac{(x^2 - 9)}{(9x^2 + 24x)}$

Factorize:

$\frac{3x + 8}{36 - 2x} * \frac{(x^2 - 9)}{3x(3x + 8)}$

Cancel out 3x + 8

$\frac{1}{36 - 2x} * \frac{(x^2 - 9)}{3x}$

Factorize:

$\frac{1}{2(18 - x)} * \frac{(x^2 - 9)}{3x}$

Combine

$\frac{x^2 - 9}{2*3x(18 - x)}$

$\frac{x^2 - 9}{6x(18 - x)}$

Express the numerator as a difference of two squares

$\frac{(x - 3)(x+3)}{6x(18 - x)}$

Hence:

$\frac{3x + 8}{36 - 2x} / \frac{27x^2 + 72x}{3x^2 - 27} = \frac{(x - 3)(x+3)}{6x(18 - x)}$

8 0

3 years ago

How do i solve for <br> (2x/5)+1=13/5

NNADVOKAT [17]

Answer:

x = 4

Step-by-step explanation:

$\frac{2x}{5} +1 = \frac{13}{5}$
$\frac{2x+5}{5} = \frac{13}{5}$ divide both sides by 5
2x + 5 = 13 subtract 5 from both sides
2x = 8 divide both sides by 2
x = 4

5 0

3 years ago