Determine the equation of a line in standard form that represents Kelsa’s training progress. Her progress corresponds to the poi
nts (1, 9.5) and (8, 6)
1 answer:
We first get the gradient of the equation of a line by taking the
change in y over change in x
Hence our gradient will be
(6-9.5)/(8-1)=-3.5/7=0.5
Taking an arbitrary point(x,y) and using our gradient we get
and one of the points above we get
(y-6)/(x-8)=0.5
y-6=0.5*(x-8)
y-6=0.5x-4
y=0.5x+2 or y=1/2x+2
which is the line of our equation the answer we are
asked for.
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