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Darya [45]
2 years ago
13

A? B? C? D? Number 10 on conexus <3 If correct I’ll give brainlest

Mathematics
2 answers:
Nikitich [7]2 years ago
6 0

Answer:

B

Step-by-step explanation:

ZanzabumX [31]2 years ago
4 0
D lol exactly yiu yeah arte yr
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Please Explain/Show Your Work! Thank You!
cestrela7 [59]

Y1 = 725

Y2 = 579

Y3 = 696

Y4 = ?

Y1 + Y2 + Y3 = 100%

725 + 579 + 696 = 2000

10% of 2000 = 2000 x .10 = 200

2% of 2000 = 2000 x .02 = 40

112% = 2000 + 200 + 40 = 2240

The answer is Y4 = 2240.

4 0
3 years ago
write an expression that shows how you can multiply 9x475 using expanded form and the distributive property
Harlamova29_29 [7]
   +6 +4
       475
 ×     9
------------
   4275
6 0
3 years ago
a meal cost $15. we gave the waiter $18 and told him that the difference was his tip. what percent of the cost of the meal was t
Stella [2.4K]
18 - 15 = 3
3/15 = n/100
15n = 300
n = 20
6 0
2 years ago
Read 2 more answers
I don't understand this
mars1129 [50]
The GCF is 7!!:))))))
8 0
2 years ago
If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices
kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]

Where det(A) = ad - bc # 0 so A is nonsingular:

Then the transposed version of A is

A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]

Then the inverted version of transposed A is

(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]

The inverted version of A is:

A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]

The transposed version of inverted A is:

(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]

We can see that

(A^T)^{-1} = (A^{-1})^T

So this theorem is true for 2 x 2 matrices

3 0
3 years ago
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