7.
Mean = 104
Median = 14
Mode = 14
Range = 30
8.
Mean = 20.41
Median = 17
Mode = 13
Range = 8
Answer:
The equation that represents the population after T years is
![P_{t} = 7,632,819,325 [1 +\frac{1.09}{100} ]^{T}](https://tex.z-dn.net/?f=P_%7Bt%7D%20%20%3D%207%2C632%2C819%2C325%20%5B1%20%2B%5Cfrac%7B1.09%7D%7B100%7D%20%5D%5E%7BT%7D)
Step-by-step explanation:
Population in the year 2018 ( P )= 7,632,819,325
Rate of increase R = 1.09 %
The population after T years is given by the formula
![P_{t} = P [1 +\frac{R}{100} ]^{T}](https://tex.z-dn.net/?f=P_%7Bt%7D%20%20%3D%20P%20%5B1%20%2B%5Cfrac%7BR%7D%7B100%7D%20%5D%5E%7BT%7D)
-------- (1)
Where P = population in 2018
R = rate of increase
T = time period
Put the values of P & R in above equation we get
This is the equation that represents the population after T years.
Domains: 7, -7, 1, 3
Ranges: 3, -5, -2, -9
It is a function because all of the domains are different numbers. If they were the same then this would not be a function.
The first step to determining the answer to this item is to calculate for the effective interest using the equation,
ieff = (1 + i/m)^m - 1
where ieff is the effective interest, i is the given interest and m is the number of compounding period.
Part A: m in this item is equal to 12.
Substituting,
ieff = (1 + 0.10/12)^12 - 1 = 0.1047
The amount of money after n years is calculated through the equation,
An = A(1 + ieff)^n
If An/A = 2 then,
2 = (1 + 0.1047)^n
The value of n is 6.96 years
Part B: For the continuously compounding,
An = Ae^(rt)
An/A = 2 = e^(0.10t)
The value of t is equal to 6.93 years.
Hence, the answers:
<em>Part A: 6.96 years</em>
<em>Part B: 6.93 years</em>
Answer:
1: a=31/2 - 3s/2 2: a=243/16 - 23s/16
Step-by-step explanation:
