Calculate the interest in a year
Multiply the annual percentage of interest by the investment to find the interest.
interest in a year = 2% × 1,000
interest in a year = 0.02 × 1,000
interest in a year = 20
The annual interest is $20
Calculate the interest after 10 years
Multiply the annual interest by 10
interest 10 years = 20 × 10
interest 10 years = 200
The sum of interest after 10 years is $200
Find total investment
investment = first investment + interest in 10 years
investment = 1,000 + 200
investment = 1,200
The investment will be worth $1,200 in 10 years
Answer:
<u>First question answer:</u> The limit is 69
<u>Second question answer:</u> The limit is 5
Step-by-step explanation:
For the first limit, plug in 
in the expression 
, that's the answer for linear equations and limits.
So we have:
The answer is 69
For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value 
into the simplified expression to get the correct answer. Shown below:
<em>Now putting 1 in 
gives us the limit:</em>
So the answer is 5
The answer is C because since the answer is 4 and if u look at c it would equal to 4.
Answer: The value of John's silver collection changes at a faster rate than the value of John's baseball card collection.
V = 500(1.05)2t + 600(0.95)t
Step-by-step explanation:
