3 years ago

Help only have 5 mins

Mathematics

1 answer:

stepladder [879]3 years ago

6 0

4
2.5 -5 that should be it i believe

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√48a^4 b^5 c^3 d simplify and keep it in radical form

Morgarella [4.7K]

I will assume the square root extends all the way across.

$\sqrt{48a^4b^5c^3}$

$\sqrt{2^4\cdot3\cdot a^4b^5c^3}$

$\sqrt{(2^2)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}$

$\sqrt{(4)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}$

$\sqrt{(4\cdot a^2 \cdot b^2 \cdot c)^2\cdot3\cdot b\cdot c}$

$4\cdot a^2\cdot b^2\cdot c\sqrt{3\cdot b\cdot c}$

$\boxed{4a^2b^2c\sqrt{3bc}}$

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3 years ago

Name an angle bisector shown in the figure. DE AB GB CF

expeople1 [14]

Answer:

Step-by-step explanation:

we know that

An angle bisector is a line that divide an angle into two equal angles.

In this problem

$m\angle ACF=m\angle FCD$ ---> given problem