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3 years ago

Examine the work shown. Explain the error and find the correct result.

2 answers:

3 0

There is no mistake unless you change the thing to the thing
2(4-16)-30
8-32+30
then eyah hope this helps and hope i can get a brainly?

NARA [144]3 years ago

3 0

$2\left(4-16\right)-\left(-30\right) \ \textgreater \ Follow\;PEMDAS \ \textgreater \ 4-16= -12$

$2\left(-12\right)-\left(-30\right) \ \textgreater \ \mathrm{Apply\:rule\:}a\cdot \left(-b\right)\:=\:-a\cdot \:b$
$2\left(-12\right)=-2\cdot \:12=-24 \ \textgreater \ 24-\left(-30\right)$

$\mathrm{Apply\:rule\:}-\left(-a\right)\:=\:+a \ \textgreater \ -\left(-30\right)=+30 \ \textgreater \ -24+30=6$

Therefore they did not apply the correct rule at the end giving the wrong answer.

Hope this helps!

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One minute after take off, an airplane altitude was 4,000 feet. Three minutes later , it was 20,000 feet what was the planes ave

Temka [501]

Answer:

The average altitude change of plane with time is 8,000 feet per min .

Step-by-step explanation:

Given as :

The initial height of plane after 1 min take off = 4,000 feet

The final height of plane after 3 min later = 20,000 feet

Let The rate of change of altitude in feet per min = s feet per min

Now, According to question

The change in altitude = final altitude - initial altitude

Or, D = 20,000 feet - 4,000 feet

I.e Distance change = 16,000 feet

The change in time = final time - initial time

Or T = 3 min - 1 min

I.e Time change = 2 min

Speed = $\dfrac{\textrm Distance}{\textrm Time}$

So, s = $\frac{16,000}{2}$ feet per min

∴ s = 8,000 feet per min

So, Rate of change of altitude with respect to time = s = 8,000 feet per min

Hence The average altitude change of plane with time is 8,000 feet per min . Answer

5 0

3 years ago

The length of a rectangle is 3 times the width. If

Margaret [11]

Answer:

Length = 27 metresWidth = 9 meters

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

For the function f x equals square root x ^ 3 - x, State the condition that must be satisfied for the FX to be Define. Then, sol

Svetradugi [14.3K]

Answer:

Domain: $[-1,0]\cup [1,\infty )$

Step-by-step explanation:

Since we know that a square root function is not defined for negative numbers. In order our function to be defined values inside radical must be greater than or equal to zero.

Our function will be defined when $x^{3} -x\geq 0$

$x(x^{2} -1)\geq 0$

$x(x-1)(x+1)\geq 0$

$1\geq x\leq 0$ or $x\geq1$

Now we will use number line method of solving inequalities to check whether our answer is right or not.

Let us try -2, -1/2, 1/2 and 2 to check which conditions meet our criteria.

$-2^{3} --2\geq 0\\-6\leq 0$

$(\frac{-1 }{2}) ^{3} -(\frac{-1}{2}) \geq0$

$\frac{-1}{8} +\frac{1}{2} \geq 0\\\frac{3}{8} \geq 0$

$(\frac{1 }{2}) ^{3} -\frac{1}{2} \geq0$

$\frac{1}{8} -\frac{4}{8} \leq 0$

$2^{3} -2\geq 0\\6\geq 0$

Therefore, we can see that our function is defined when $1\geq x\leq 0$ or $x\geq1$ and domain of f(x) is $[-1,0]\cup [1,\infty )$ .

4 0

3 years ago

Graph each of the following lines without using a table of values a. y = 2⁄3x - 5 b. 6x - 2y + 5 = 0

DedPeter [7]

$\text{Graph the lines:}\\\\a. \,\,y = 2/3x - 5\\\\\text{For this equation, we are given our beginning point and slope}\\\\\text{The beginning point is -5, so you would put a point at -5 on the y-axis}\\\\\text{Since the slope is 2/3, we would use the rise/run method}\\\\\text{In this case, starting from -5 on the y-axis, you would go up 2 and to the}\\\text{right 3, then place your point where you ended up.}\\\\\text{Keep using the rise/run method to create the rest of the points}\\\\$

$b.\,\, 6x - 2y + 5 = 0\\\\\text{Turn the equation into slope form:}\\\\ 6x - 2y + 5 = 0\\\\-2y=-6x-5\\\\y=3x+5/2\\\\\text{The beginning point is at 5/2, or 2.5}\\\\\text{Place the point at 2.5 on the y-axis}\\\\$