The center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
<h3>Equation of a circle</h3>
The standard equation of a circle is expressed as:
x^2 + y^2 + 2gx + 2fy + c = 0
where:
(-g, -f) is the centre of the circle
Given the equations
x^2 +y^2 – 12x – 2y +12 = 0
Compare
2gx = -12x
g = -6
Simiarly
-2y = 2fy
f = -1
Centre = (6, 1)
Hence the center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
Learn more on equation of a circle here: brainly.com/question/1506955
5) x=-4
6)p=8
7) x=40
8) a=5
9) b=16
10) q=2
Answer:
slope: -3
y-int: -1
Step-by-step explanation:
Answer:
Its below!
Step-by-step explanation:
a=l*w
9=(3+x) (2+x)
9=6+3x+2x+x^2
9=6+5x+x^2
3=5x+x^2
Hope this helps!! :)
Answer:
Step-by-step explanation:
so if you put Ln(0.99) into your calculator it gives you a negative answer. so we know that this problem will be decay.
next the answer for the above looks like 0.010050 ... so it's 1.0% for each x
