Answer:
Step-by-step explanation:
This question is too general. We can take a look at the behaviors of the two different graphs:
f(x)=3^x-3 is an exponential function whose y-intercept is (0, -2). Note that 3^0 = 1. To draw this function, we'd drawn f(x)=3^x first and then translate the whole graph down by 3 units. The graph appears in Quadrants III, IV and I, in that order.
g(x)=7x^2-3 is not an exponential function, but rather a quadratic whose graph is a parabola. Here the parabolic graph opens up. Its y-intercept is (0, -3). This graph will intersect that of f(x)=3^x-3 in two places.
A: False. It is g that has minimum y value of -3. The minimum y value of f is -2.
B: The smallest y value f can have is just above y = -2. y = -2 is the horizontal asymptote for this function. The smallest y value g can have is -3. So B is False.
C: True. g has the smallest possible y-value; it is -3.
D: True. The min. y-value of g is -3.
