Given sinx=-3/5 and x is in quadrant 3, what is the value of tan x/2?
2 answers:
Answer:
-3
Step-by-step explanation:
In the attached image we can see the tan(x/2) relation with sine and cosine
tan(x/2)=sinx/(1+cosx)
sinx=-3/5
and from the triangle we can see that the cosine is equal to -4/5 (this triangle is also called a notable triangle of sides 3,4,5 in lenght)
tan(x/2)=(-3/5)/(1-4/5)
tan(x/2)=-3
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Answer:
= 12
Step-by-step explanation:
The shape ABCDEF is an irregular polygon.
The sum of the interior angles of any regular or irregular polygon = (n - 2) x 180 (where n is the number of sides of the polygon).
Therefore, the sum of the interior angles of shape ABCDEF = (6 - 2) x 180 = 720°
So to find the value of , we need to add together all the interior angles and equal it to 720, then solve for
.
Before we do that, we need to determine angle F.
From inspection, we can see that angle F and 52° are a linear pair. We know that a linear pair of angles add up to 180°, so F + 52 = 180 ⇒ F = 180 - 52 = 128°
Therefore:
A + B + C + D + E + F = 720
(10 - 5) + 108 + (8
- 3) + (14
- 25) + 133 + 128 = 720
Collect like terms:
10 + 8
+ 14
- 5 + 108 - 3 - 25 + 133 + 128 = 720
Combine like terms:
32 + 336 = 720
Subtract 336 from both sides:
32 = 384
Divide both sides by 32:
= 12