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brilliants [131]
3 years ago
10

Given sinx=-3/5 and x is in quadrant 3, what is the value of tan x/2?

Mathematics
2 answers:
Liula [17]3 years ago
8 0
Solution is attached. İf right I'm happy

bezimeni [28]3 years ago
4 0

Answer:

-3

Step-by-step explanation:

In the attached image we can see the tan(x/2) relation with sine and cosine

tan(x/2)=sinx/(1+cosx)

sinx=-3/5

and from the triangle we can see that the cosine is equal to -4/5 (this triangle is also called a notable triangle of sides 3,4,5 in lenght)

tan(x/2)=(-3/5)/(1-4/5)

tan(x/2)=-3

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Answer:

<h2>         y = 0.25x + 2</h2>

Step-by-step explanation:

\bold{slope\, (m)=\dfrac{change\ in\ Y}{change\ in\ X}=\dfrac{y_2-y_1}{x_2-x_1}}

(0, 2)    ⇒     x₁ = 0,  y₁ = 2

(-4, 1)     ⇒     x₂ = -4,  y₂ = 1

So the slope:

\bold{m=\dfrac{1-2}{-4-0}=\dfrac{-1}{-4}=0.25}

The point-slope form of the equation of the line passing through point (x₀,y₀) and with slope m is:  y - y₀ = m(x - x₀)

m = 0.25

(0, 2)    ⇒     x₀ = 0,  y₀ = 2

Therefore:

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               y - 2 = 0.25x                  {add 2 to both sides}

               y = 0.5x + 2          ←  the slope-intercept form of the equation

5 0
3 years ago
How do you find the exterior angle of a polygon?
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Step-by-step explanation:

I didn't understand the question.

Do u want the function?

if so

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at 0=0

at 1= 3

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if ur looking for something else, please tell me.

6 0
3 years ago
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