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horrorfan [7]
3 years ago
10

The area of circle Z is 64.What is the value of r

Mathematics
1 answer:
anzhelika [568]3 years ago
7 0
About the square root of 20
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Which are the solutions of x^2 = –11x + 4?
strojnjashka [21]

This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

x^2 + 11x - 4 = 0

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}

where x_{1,2} is a compact way to indicate both solutions x_1 and x_2, while a,b,c are the coefficients of the quadratic equation, i.e. we consider the polynomial ax^2+bx+c.

So, in your case, we have a=1,\ \ b=11,\ \ c=-4

Plug those values into the formula to get

x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}

So, the two solutions are

x_1 = \frac{-11+\sqrt{137}}{2}

x_2 = \frac{-11-\sqrt{137}}{2}

3 0
3 years ago
Choose the product. -6p3(3p2 + 5p - 1) -18p5 - 30p4 + 6p3 -18p6 - 30p3 - 6p 18p3 + 6p2 - 30p4 -18p6 - 24p3
wlad13 [49]
-6p^3(3p^2 +5p -1) = -18p^5 -30p^4 +6p^3

so this is the right answer sure 
7 0
2 years ago
3z2 - 2z + 8 <br> -<br> (10z2 +7z - 12)
klemol [59]

Answer: 7z²-9z+20

Step-by-step explanation:

PEMDAS - Please Excuse My Dear Aunt Sally - Parentheses, Exponents, Multiplication, Division, Addition, Subtraction

4 0
2 years ago
Veronica Foaley sells evening jackets sewn with metallic threads and beads. She wants to set a price of $600 for a jacket. The m
boyakko [2]
The most she can pay for the jacket is $375 (=600/(100%+60%)) assuming this is the cost of the jacket before it sewn with metallic threads and beads. A markup is a difference between the production cost and the selling price in order to cover the additional cost related to the product. Based on the data, she wants to keep the 60% for covering the cost.
6 0
3 years ago
Read 2 more answers
Mr.Choi has a class of 17 students. He can spend $17 on each student to buy math supplies for the year. He first bugs all his st
Reika [66]
Multiply 17(number of students) and 17(amount he’s spending on each student)
So 17x17=289
Then subtract what he used which is 97.41
So 289-97.41= 191.59

He has $191.59 left
5 0
3 years ago
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