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AfilCa [17]
3 years ago
11

It would be great if i can get some help. Thank you. Include explanation please

Mathematics
1 answer:
NISA [10]3 years ago
7 0

We're given two sides and the included angle and asked to find the third side. That's the Law of Cosines.


c^2 = a^2 + b^2 - 2 a b \cos C


c = \sqrt{15^2 + 20^2 - 2 (15)(20) \cos 50^\circ} \approx 15.5 \textrm{ feet}



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If the framed picture is shaped like a square and has a 12 square foot surface area, then the answer is yes, it will fit flush against the edge of the crate.

Given Part A:

the volume of the cube = 64 cubic feet

therefore, ∛64 = 4 feet

hence one edge measures 4 feet.

Now for Part B:

the area of the square is 12 square feet.

hence, √12 = 3.36 feet.

we can observe that 3.46<4

which indicates that the area covered by the painting is less than that of the one side of the crate, which makes it easy for the painting to fit in the crate.

Hence the painting will fit a side of crate.

Learn more about Area and Perimeter here:

brainly.com/question/24571594

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Your question was incomplete. Please find the missing content here.

While packing for their cross-country move, the Chen family uses a that has the shape of a cube. PART A PART B If the crate has the volume V = 64 cubic feet, The Chens want to pack a large, framed painting. If an area of 12 square feet , will the painting fit flat what is the length of one edge? the framed painting has the shape of a square with against a side of the crate? Explain.

3 0
2 years ago
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Doss [256]

Answer: A) 5 x 1/2

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Answer:

30 game boxes

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Earth, Mars, Saturn, Uranus and Neptune revolve around the sun. Earth takes 1 year, Mars 2 years, Saturn 30 years, Uranus 84 yea
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Answer:

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3 years ago
The area of a mirror is 225 Square inches, it's width is
Zepler [3.9K]

NO. The mirror will not fit in a space that is 15 inches by 16 inches

<em><u>Solution:</u></em>

Given that area of mirror is 225 square inches

width = 13\frac{3}{4} \text{ inches }

Converting the above mixed fraction we get,

width = 13\frac{3}{4} = \frac{13 \times 4 + 3}{4} = \frac{55}{4} \text{ inches }

Let us find the length of mirror

The area of mirror is given as:

area of mirror = length x width

Substituting the given values,

225 = length \times \frac{55}{4}\\\\length = 225 \times \frac{4}{55}\\\\length = 225 \times 0.0727\\\\length = 16.36

Thus length of mirror is 16.36 inches

<em><u>Will the mirror fit in a space that is 15 inches by 16 inches?</u></em>

NO. The mirror will not fit in a space that is 15 inches by 16 inches

Because length of mirror is 16.36 inches whereas the given space is 15 inches long

16.36 > 15 so the length of mirror will not fit inside the space

Also width of mirror is \frac{55}{4} = 13.75 inches which is less than the given space whose width is 16 inches

13.75 < 16 so the width of mirror will not fit inside the space

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4 years ago
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