The answer is c. To get to (-2,1) from (5,-4), you have to add subtract 7 from 5 and add 5 to 1.
Given :
To Find :
the absolute minimum and absolute maximum values of f on the given interval
[-1,2] .
Solution :
Now , getting first order differential equation and equating its equal to zero.

So , x=0 is critical point .
Now , coefficient of
is positive .
Therefore , it is increasing function after x=0 .
So , min value will be at , x=0.

And maximum value will be the maximum at the x=2 because it is increasing function .

Therefore , max and min value is 9 and -3 respectively .
Hence , this is the required solution .
Answer:
46−5y
Step-by-step explanation:
5(10−y)−4
Use the distributive property to multiply 5 by 10−y.
50−5y−4
Subtract 4 from 50 to get 46.
46−5y
Graph if needed: