Answer:
36cm(squared)
Step-by-step explanation:
The top rectangle is 8*(6-4)2=16cm
the bottom is the square which is 4*5=20cm
16+20=36cm(squared)
Answer:
0.84
Step-by-step explanation:
Given that Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 100 disks are summarized as follows:
P(A) = 0.86, P(B) = 0.79, P(A') = 0.14, P(AUB) = 0.95
We are to find out P(A'UB)
We have
![P(A'UB) = P(A')+P(B)-P(A' \bigcap B)\\= 1-P(A) +P(B)-[P(B)-P(A \bigcap B)]\\= 1-0.86+0.79-P(B)+[tex]P(A'UB)=0.14+0.79-0.79+0.70\\=0.84](https://tex.z-dn.net/?f=P%28A%27UB%29%20%3D%20P%28A%27%29%2BP%28B%29-P%28A%27%20%5Cbigcap%20B%29%5C%5C%3D%201-P%28A%29%20%2BP%28B%29-%5BP%28B%29-P%28A%20%5Cbigcap%20B%29%5D%5C%5C%3D%201-0.86%2B0.79-P%28B%29%2B%5Btex%5DP%28A%27UB%29%3D0.14%2B0.79-0.79%2B0.70%5C%5C%3D0.84)
P(A \bigcap B)[/tex]
Answer: The given logical equivalence is proved below.
Step-by-step explanation: We are given to use truth tables to show the following logical equivalence :
P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P)
We know that
two compound propositions are said to be logically equivalent if they have same corresponding truth values in the truth table.
The truth table is as follows :
P Q ∼P ∼Q P⇔ Q ∼P ∨ Q ∼Q ∨ P (∼P ∨ Q)∧(∼Q ∨ P)
T T F F T T T T
T F F T F F T F
F T T F F T F F
F F T T T T T T
Since the corresponding truth vales for P ⇔ Q and (∼P ∨ Q)∧(∼Q ∨ P) are same, so the given propositions are logically equivalent.
Thus, P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P).
Answer:A
Step-by-step explanation:
