Question

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Answer 1

Answer:

1 =d

2=a

3=f

4=b

5=e

6=c

Step-by-step explanation:

We are given a right angled triangle ABC

AB =  c

BC =  a

AC =  b

Using Trigonometric ratio:

$Sin\theta = \frac{Perpendicular}{Hypotenuse}$

$Sin\theta = \frac{BC}{AB}$

For perpendicular BC base angle for sine is ∠A

So, $Sin A = \frac{a}{c}$

So, 1 = d

Using Trigonometric ratio:

$Sin\theta = \frac{Perpendicular}{Hypotenuse}$

$Sin\theta = \frac{opposite}{Hypotenuse}$   --1

$Sin\theta = \frac{AC}{AB}$

For perpendicular AC base angle for sine is ∠B

So, $Sin B = \frac{b}{c}$

So, 2 = a

Using 1

$Sin\theta = \frac{opposite}{Hypotenuse}$

So, 3 = f

$Cos \theta = \frac{Base}{Hypotenuse}$

$Cos \theta = \frac{Adjacent}{Hypotenuse}$

So, 4 = b

Using Trigonometric ratio:

$Tan\theta = \frac{Perpendicular}{Base}$

$Tan\theta = \frac{BC}{AC}$

For Base AC base angle for Tan is ∠A

So, $tan A = \frac{a}{b}$

So, 5 = e

Using Trigonometric ratio:

$Tan\theta = \frac{Perpendicular}{Base}$

$Tan \theta = \frac{AC}{BC}$

For Base BC base angle for Tan is ∠B

So, $tan B = \frac{b}{a}$

So, 6 = c

Answer 2

1. (a/c)
= (opposite/hypotenuse A)
= sin A (d)

2. (b/c)
= (opposite/hypotenuse B)
= sin B (a)

3. (opposite/hypotenuse)
= sine (f)

4. (adjacent/hypotenuse)
= cosine (b)

5. (a/b)
= (opposite/adjacent A)
= tan A (e)

6. (b/a)
= (opposite/adjacent B)
= tan B (c)

hope it helps!