the answer is the first one y<0
Y α xz
y = kxz y = 72, when x = 6, and z = 4
72 = k*6*4
72 = k*24
24k = 72
k = 72/24
k = 3.
<span>y = kxz
</span>
<span>y = 3xz </span>
Finding y, when x = 3, z = 5.
y = 3xz
y = 3*3*5
y = 45
Answer:
131
Step-by-step explanation:
1/2m -3/4n = 16
solve your system of equations.
n=8: (1/2)(m)+((−3)/4)(n)=16
Solve n=8 for n:
Substitute (8) for n in 1/2m+−3/4n=16:
1/2m+−3/4n=16
1/2m+−3/4(8)=16
1/2m−6=16(Simplify both sides of the equation)
1/2m−6+6=16+6(Add 6 to both sides)
1/2m=22
1/2m1/2 = 22 / 1/2(Divide both sides by 1/2)
m=44