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3 years ago

Can you help me round 3,418,913 to the nearest thousand

Mathematics

2 answers:

Kamila [148]3 years ago

6 0

3,419,000 because the 913 rounds the number up

serious [3.7K]3 years ago

6 0

<span>3,418,913 to the nearest thousand is 3,419

</span>

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An election ballot asks voters to select four city commissioners from a group of eight candidates. In how many ways can this be

saul85 [17]

The number of combinations of the 8 candidates taken 4 at a time is:
$8C4=\frac{8!}{4!4!}=70\ ways$

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3 years ago

I Was Not That Day On College, I Don't Have The Formulas To Study

gavmur [86]

Answer:

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2 years ago

Find the minimum and maximum values of the function subject to the given constraint. (if an answer does not exist, enter dne.) f

nata0808 [166]

Via Lagrange multipliers:

$L(x,y,\lambd)=x^2y+x+y+\lambda(xy-5)$
$L_x=2xy+1+\lambda y=0$
$L_y=x^2+1+\lambda x=0$
$L_\lambda=xy-5=0$

$\underbrace{10}_{2xy}+1+\lambda y=0\implies \lambda=-\dfrac{11}y$
$xy=5\implies y=\dfrac5x\implies\lambda=-\dfrac{11}5x$

$\impliesx^2+1+\left(-\dfrac{11}5x\right)x=0\implies x^2=\dfrac56\implies x=\pm\sqrt{\dfrac56}$
$xy=5\implies y=\pm\sqrt{30}$

At these points, we get local minima of $f\left(\pm\sqrt{\dfrac56},\pm\sqrt{30}\right)=\pm2\sqrt{30}$ .

- - -

Another way to do this is to make $f(x,y)$ a function independent of $y$ , which is made possible by the constraint.

$xy=5\implies y=\dfrac5x$
$\implies f(x,y)=f\left(x,\dfrac5x\right)=F(x)=6x+\dfrac5x$
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and so on.

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3 years ago

Find the length of an arc of a 8inch radius circle if the arc measures 45 degrees

lidiya [134]

45° is exactly 1/8 of a full circle (45/360 = 1/8) <span>
So the length of the arc would be 1/8 of a full circumference:
C = 2π r
C = 2π(8)
C = 16π

Take 1/8 of this:
1/8C = (1/8)16π = 2π

Answer:
Exact answer --> 2π inches
(Approx. answer --> 6.28 inches)</span>

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2 years ago

What 2 numbers can be multiplied to get -4 but when added equals 3 ?

forsale [732]

Answer:

4 and -1

Step-by-step explanation:

Solving for two variables can be done by setting up a system of equations. In this case you have two numbers 'x' and 'y' when multiplied is -4:

x*y = -4

When the same two number are added together it's 3:

x + y = 3

Using the second equation to solve for 'x', you can then use that expression to substitute for 'x' in the first equation:

x = 3 - y

y(3 - y) = -4 or 3y - y² = -4 or y² - 3y = -4

Factor: (y - 4)(y + 1)

Solve for y: y = 4 or -1

If y = 4, then x = -1 or when y = -1, x = 4, so the two numbers are 4 and -1:

(4)(-1) = 4 and 4 + -1 = 3

6 0

3 years ago