<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
Answer:
x is 11
Step-by-step explanation:
We know the slope (3/4) and a point (3,-4), so we can use point-slope form (y-y1=m(x-x1)
Substitute the numbers into the equation
y--4=3/4(x-3)
simplify
y+4=3/4(x-3)
do the distributive property
y+4=3/4x-9/4
subtract 4 from both sides
y=3/4x-25/4
this is the equation of the line.
Since it says that (x,2) is a point in the equation, we can substitute it into the equation
2=3/4x-25/4
add 25/4 to both sides
33/4=3/4x
multiply by 4/3
11=x
we can double check by plugging (11,2) into the equation of the line.
2=3/4(11)-25/4
2=33/4-25/4
2=2
it works! :)
Hope this helps!
Answer:
x=3
Step-by-step explanation:
I believe the correct answer would be 5,1,3 :)
