<em>Answer:</em>
<em>The answer to both problems is </em><em><u>GRAPH</u></em>
<em>I hope this helps:)</em>
Answer:
Not Sure Without Slope
Step-by-step explanation:
you could use the formula y-y1=m(x-x1)(point slope form) where m is the slope, y1 is the first y point and x1 is the first x point.
For example if a line has slope 3 and passes through the points (5, 6), then the formula you would solve is y-6=3(x-5) to find the equation of the line in slope-intercept form and you should know what to do with everything else.
Domain: {-2, 4, 5}
Range {-6, 2, 3}
Mean 6.6
Median 6
Mode 3
Range 10
not positive on the 6.6 but the rest should be good
The sign of f on the interval -7/3 < x < -3/5 is always positive.
<h3>How to solve for the sign on the interval</h3>
We have the equation
(5x+3)(x−2)(3x+7)(x+5) > 0
Now when f(x) > 0
Then -7/3 < x < -3/5
This would tell us that the sign would become positive when it changes from the less than to greater than sign
<h3>Complete Question</h3>
f(x)=(5x+3)(x-2)(3x+7)(x+5) has zeros at x=-5, x=-7/3, x=-3/5, and x=2
What is the sign of f on the interval -7/3<x<-3/5?
answer choices
f is always positive on the interval
f is always negative on the interval
f is sometimes positive and sometimes negative on the interval
f is never positive or negative on the interval
Read more on polynomials here:
brainly.com/question/2833285
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