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Olegator [25]
3 years ago
6

Which is the equation for a line that passes through the points (3, 1) and (4, -1) ?

Mathematics
1 answer:
Lorico [155]3 years ago
8 0

Answer:

-2x +7

Step-by-step explanation:

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Aileen can read 1.5 pages for every page her friend can read. Aileen's mom was very excited and she say to Aileen: ''so, if your
lana [24]
No because 20 times 1.5 is 30 not 25
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4 years ago
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The volume of both of these trapezoidal prisms is 24 cubic units. Their heights are 6 and 8 units, as labeled. What is the area
Ne4ueva [31]

Answer:

area of a trapezoidal base  of each prism with heights  6 and 8 units are 4 square units and 3 square units respectively

Step-by-step explanation:

Let us first be aware of formula of volume for any regular geometrical figure.

Fundamental formula for  volume for any regular geometrical figure is.

volume = area of cross section of object*  height of object (A)

In the problem stated area of cross section of object will be  area of a trapezoidal base.

Given in the question is

Volume of both the trapezoidal prisms = 24 cubic units

*************************************************************************************

For prism with height 6 unit

Substituting the value of height and volume in formula for trapezoidal prisms

24 = 6 * area of a trapezoidal base

=> area of a trapezoidal base = 24/6 = 4 square units

*************************************************************************************

For prism with height 8 unit

Substituting the value of height and volume in formula for trapezoidal prisms

24 = 8 * area of a trapezoidal base

=> area of a trapezoidal base = 24/8 = 3 square units

*************************************************************************************

Therefore area of a trapezoidal base  of each prism with heights  6 and 8 units are 4 square units and 3 square units respectively.

7 0
3 years ago
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Find the equation of the line passing<br> through the points (2, 1) and (5, 10).<br> y= [? ]x + [ ]
Kamila [148]

Answer:

y=4x-14

y=4x-14(Y2-Y1)/ (X2-X1) = slope

y=4x-14(Y2-Y1)/ (X2-X1) = slopey=Mx+b. M= slope B= y-int.

y=4x-14(Y2-Y1)/ (X2-X1) = slopey=Mx+b. M= slope B= y-int.(10-2) (6-4)= 8/2

y=4x-14(Y2-Y1)/ (X2-X1) = slopey=Mx+b. M= slope B= y-int.(10-2) (6-4)= 8/2=4

y=4x-14(Y2-Y1)/ (X2-X1) = slopey=Mx+b. M= slope B= y-int.(10-2) (6-4)= 8/2=4(4,2)-> choose one point then plug in

y=4x-14(Y2-Y1)/ (X2-X1) = slopey=Mx+b. M= slope B= y-int.(10-2) (6-4)= 8/2=4(4,2)-> choose one point then plug in2 = 4(4)+b

y=4x-14(Y2-Y1)/ (X2-X1) = slopey=Mx+b. M= slope B= y-int.(10-2) (6-4)= 8/2=4(4,2)-> choose one point then plug in2 = 4(4)+b2 = 16+b

y=4x-14(Y2-Y1)/ (X2-X1) = slopey=Mx+b. M= slope B= y-int.(10-2) (6-4)= 8/2=4(4,2)-> choose one point then plug in2 = 4(4)+b2 = 16+bb= -14

y=4x-14(Y2-Y1)/ (X2-X1) = slopey=Mx+b. M= slope B= y-int.(10-2) (6-4)= 8/2=4(4,2)-> choose one point then plug in2 = 4(4)+b2 = 16+bb= -14y= 4x-14

hope that helps wyoo

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3 years ago
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Find the value of w to the nearest tenth using the tangent ratio for ZA.
Anna11 [10]

Answer:

w ≈ 13.8

Step-by-step explanation:

using the tangent ratio in the right triangle

tan36° = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{10}{w} ( multiply both sides by w )

w × tan36° = 10 ( divide both sides by tan36° )

w = \frac{10}{tan36} ≈ 13.8 ( to the nearest tenth )

7 0
2 years ago
What is the solution set of (x-2)(x-3) = 2?<br> O (1.4)<br> O (2, 3)<br> O [4,5)
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The answer is x1 = 1 , x 2 = 4.
(1,4)
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3 years ago
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