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kodGreya [7K]
3 years ago
9

What is the value of 4 in the number 546 210

Mathematics
2 answers:
timurjin [86]3 years ago
6 0
<span>The correct answer is 40,000.

Explanation<span>:
The 4 is in the ten-thousands place. This means its value is 4(10000)=40000.</span></span>
Komok [63]3 years ago
3 0

Answer:

4 has value of 10,000 which ten thousand place value.

Step-by-step explanation:

Given number 546210

We have to find the value of 4 in given number 546210.

We write the given number in value form as ,

546210 = 5×100000 + 4× 10000 + 6 ×1000 + 2×100 + 10  

in words it is written as

Here, 4 has value of 10,000 which ten thousand place value.  

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Answer:

1=90

2=282.6

Step-by-step explanation:

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3 years ago
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kirill115 [55]

Answer:

25

Step-by-step explanation:

10÷1/4=25

3 0
3 years ago
3x+2y=18 , 8x+6y=50 if x represents the cost of a birthday card and y represents the cost of a thank you note how much does each
elena55 [62]

(-9x-6y=-54) +(8x+6y=50)= -x=-4; x=4
3(4)+2y=18
12+2y=18
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7 0
4 years ago
Land in downtown Columbia is valued at $10 a square foot. What is the value of a triangular lot with sides of lengths 119, 147,
stiks02 [169]

Answer:

$87,461

Step-by-step explanation:

Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft

where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.

S = (119 + 147 + 190) / 2 = 456/ 2 = 228

Using Heron's formula which gives the area in terms of the three sides of the triangle

= √s(s – a)(s – b)(s – c)

Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)

=> √228 (109)(81)(38)

= √228(335502)

=√76494456

= 8746.1109071 * $10

= 87461.109071

≈$87,461

Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.

6 0
3 years ago
One number is 5 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 779,
Harrizon [31]

Answer:

97, 485, 197

Step-by-step explanation:

<u>Given</u>:

  • First number = a
  • Second number = b
  • Third number = c

<u>Then we have:</u>

  • b = 5a
  • c = 100+a
  • a + b + c = 779

<u>Substituting b and c in the third equation:</u>

  • a + 5a + 100+a = 779
  • 100 + 7a = 779
  • 7a = 779- 100
  • 7a=679
  • a= 679/7
  • a = 97
  • b= 5*97 = 485
  • c = 100+ 97 = 197
8 0
3 years ago
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