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lions [1.4K]
3 years ago
11

Answerrr jsjsjjsjsjsjsjsjsjsjjsjsjsjsjs

Mathematics
1 answer:
vredina [299]3 years ago
7 0

\dfrac{ \sqrt{27} + \sqrt{75} }{\sqrt{48}} = \dfrac{ \sqrt{9 \times 3} + \sqrt{25 \times 3}}{\sqrt{16 \times 3}} = \dfrac{3 \sqrt{3} + 5 \sqrt{3}}{4 \sqrt{3}} = \dfrac{8 \sqrt{3}}{4 \sqrt{3}} = 2



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the area of a triangle is 124 square units. what would it's new area be if its base was half as long and its height was three ti
Montano1993 [528]
To solve this problem you must apply the proccedure shown below:

 1. You have that the formula for calculate the area of a triangle is:

 A=bh/2

 Where A is the area of the triangle, b is the base of the triangle and h is the height of the triangle.

 bh/2=124
 bh=124x2
 bh=248

 2. The problem asks for the new area of the triangle <span>if its base was half as long and its height was three times as long. Then, you have:

 Base=b/2
 Height=3h

 3. Therefore, when you substitute this into the formula for calculate the area of a triangle, you obtain:

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 (A' is the new area)

 A'=(b/2)(3)/2
 A'=3bh/4

 4. When you substitute bh=248 into </span>A'=3bh/4, you obtain:
<span>
 A'=186 units</span>²
<span>
 The answer is: </span>186 units²
3 0
3 years ago
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