All categories

2 years ago

What would you expect to happen if a pay rate of $13.50 per hour were offered?

Mathematics

1 answer:

oksian1 [2.3K]2 years ago

6 0

Answer:

I'd take the job... althou I am a kid so money is like worth a lot to me

Hope this helps

plz like and brainly :D

would help me

You might be interested in

CAN ANYONE HELP ME FIND THE ANSWERS TO QUESTION 2 !? ASAP .. DUE IN 15 MINS :(

Debora [2.8K]

Omg if I had my TI calculator I could help you !!

7 0

2 years ago

A bag contains 70 pencils out of which 15 are green and 30 blue.(i)How many pencils of other colours. are in the bag?(ii)A penci

Bas_tet [7]

Answer:

i) 25

ii) 30:70; 30 out of 70 pencils will be blue.

Step-by-step explanation:

i) 70 - (15+30)= 25 other colors in the bag.

ii) 30:70

4 0

3 years ago

A random sample of 10 single mothers was drawn from a Obstetrics Clinic. Their ages are 22, 17, 27, 20, 23, 19, 24, 18, 19, and

Sever21 [200]

Answer:

The two-tailed P value equals 0.2308

By conventional criteria, this difference is considered to be not statistically significant.

Step-by-step explanation:

Given is a random sample of 10 single mothers

the ages are given as

22, 17, 27, 20, 23, 19, 24, 18, 19, and 24 years

H0: Mean = 20

Ha: Mean not equals 20

(two tailed test at 5% significance level)

The hypothetical mean is 20.00

The actual mean is 21.30

The difference between these two values is 1.30

The 95% confidence interval of this difference:

From -0.99 to 3.59

t = 1.2851

df = 9

standard error = 1.012

The two-tailed P value equals 0.2308

By conventional criteria, this difference is considered to be not statistically significant.

6 0

3 years ago

Factor Completely: 2x2 − 18

tangare [24]

To factor the given function, find a term that is divisible by both terms. For this problem, the factor would be 2, since 2x^2 and -18 are both divisible by 2.

2(x^2 - 9)

You could further factor out x^2 - 9 because it is factorable by (x - 3) and (x + 3). Thus, it would be

2(x -3)(x+3)

3 0

2 years ago

Read 2 more answers

According to a study done by a university student, the probability a randomly selected individual will not cover his or her mou

solniwko [45]

Complete Question

According to a study done by a university student, the probability a randomly selected individual will not cover his or her mouth when sneezing is 0.267 Suppose you sit on a bench in a mall and observe people's habits as they sneeze

(a) What is the probability that among 18 randomly observed individuals exactly 6 do not cover their mouth when sneezing?

Answer:

$P(X=6)=(0.162)$