She missed 3 questions,
11/100 equals x/26
^set up this proportion
you get 286 equals 100x
and x equals 2.86
round this to 3 questions
to check your work, do 23/26
Dave will have $12,728 after 15 years, if he has $8000 to invest for 15 years. He finds a bank that offers an interest rate of 3.1% compounded monthly.
Step-by-step explanation:
The given is,
Investment = $ 8000
No. of years = 15 years
Interest rate, i = 3.1 %
( compounded monthly )
Step:1
For for calculating future value with compound interest monthly,
.................(1)
Where,
A = Future amount
P = Initial investment
r = Rate of interest
n = Number of compounding in a year
t = Time period
Step:2
From given values,
P = $8000
r = 3.1%
t = 15 years
n = 12 ( for monthly)
Equation (1) becomes,
A = $ 12728.48
Result:
Dave will have $12,728 after 15 years, if he has $8000 to invest for 15 years. He finds a bank that offers an interest rate of 3.1% compounded monthly.
Answer:
A)σ = 15.37 miles per hour
B) σ = 55.10 miles per hour
C) 39.73 miles per hour
Step-by-step explanation:
Formula for standard deviation is;
σ = √(Σ(x - μ)²)/(n - 1)
A) For large wild cats;
μ = Σx/n = (70 + 40 + 30 + 40 + 35 + 35 + 35 + 35 + 10)/9 = 36.67
σ = √((70 - 36.67)² + (40 - 36.67)² + (30 - 36.67)² + (40 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (10 - 36.67)²)/(9 - 1)
σ = √236.1139
σ = 15.37
B) For various birds;
μ = Σx/n = (218 + 106 + 97 + 56 + 66 + 39 + 55 + 32 + 54 + 20 + 25 + 25)/12
μ = 66.0833
σ = √((218 - 66.0833)² + (106 - 66.0833)² + (97 - 66.0833)² + (56 - 66.0833)² + (66 - 66.0833)² + (39 - 66.0833)² + (55 - 66.0833)² + (32 - 66.0833)² + (54 - 66.0833)² + (20 - 66.0833)² + (25 - 66.0833)² + (25 - 66.0833)²)/(12 - 1)
σ = √3035.72
σ = 55.10
C) difference in standard deviations = 55.10 - 15.37 = 39.73 miles per hour
Answer:
25.64 in^2
Explanation:
<span><span>60360</span>⋅π<span>r2</span></span>, where <span>r=7</span>
<span>=<span>16</span>⋅3.14⋅<span>72</span>=<span>16</span>⋅3.14⋅49=25.64</span> in^2
Answer: We are using a line regression tool to solve the parameters asked in the problem. We can use online tools or that of Excel. According to the tool, the best fit values are
Slope0.3848 ± 0.03956
Y-intercept0.6053 ± 0.6370
X-intercept-1.573
1/Slope2.598
Step-by-step explanation: Best fit lines make sure that the standard deviation at each point is minimum from the best fit line.
