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sveticcg [70]
3 years ago
9

The x-coordinate of the vertex of the equation y = 2x2 − 4x + 12 The x-coordinate of the vertex of the equation y = 4x2 + 8x + 3

Mathematics
1 answer:
dolphi86 [110]3 years ago
6 0

So since the vertex falls onto the axis of symmetry, we can just solve for that to get the x-coordinate of both equations. The equation for the axis of symmetry is x=\frac{-b}{2a}, with b = x coefficient and a = x^2 coefficient. Our equations can be solved as such:

y = 2x^2 − 4x + 12: x=\frac{4}{2*2}=\frac{4}{4}=1

y = 4x^2 + 8x + 3: x=\frac{-8}{2*4}=\frac{-8}{8}=-1

In short, the vertex x-coordinate's of y = 2x^2 − 4x + 12 is 1 while the vertex's x-coordinate of y = 4x^2 + 8x + 3 is -1.

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Hi there!

\boxed{-\frac{4x}{3}sin(2-3x) + \frac{4}{9}cos(2-3x) + C}

To find the indefinite integral, we must integrate by parts.

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Write into the format:

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