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3 years ago

7

tommy is buying used books for school. the price of the books is $180. he uses the 30%-off student discount and there is a 4% sa

les tax.

1 answer:

zaharov [31]3 years ago

7 0

Answer:

131.04

Step-by-step explanation:

0.7×180=126

1.04×126=131.04

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OleMash [197]

You have invested 1200 dollars in your mutual fund and now gained 1333 dollars. First let's solve how much money added to your investment.
=> 1333 - 1200 = 133 dollars was added to your account
=> 133 / 1200 = 0.11
Next, lets convert this to decimal value.
=> 0.11 * 100% = 11% was added to you investment.

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Mary’s pet turtle Waze mary’s pet turtle Weighs 4.094 pounds. How is this number written in word form?

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2 years ago

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A package contains 12 resistors, 3 of which are defective. If 4 are selected, find the probability of getting

s344n2d4d5 [400]

Answer:

Incomplete question, but I gave a primer on the hypergeometric distribution, which is used to solve this question, so just the formula has to be applied to find the desired probabilities.

Step-by-step explanation:

The resistors are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

12 resistors, which means that $N = 12$

3 defective, which means that $k = 3$

4 are selected, which means that $n = 4$

To find an specific probability, that is, of x defectives:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = x) = h(x,12,4,3) = \frac{C_{3,x}*C_{9,4-x}}{C_{12,4}}$

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3 years ago

John is creating a Thanksgiving display at the store where he works, using only canned pumpkin and canned green beans. He needs

mezya [45]

Answer:

The number of Pumpkin can used = 48 cans

The number of Green Beans can used = 16 cans

Step-by-step explanation:

The ratio of Pumpkin to Green Beans = 3 : 1

So, for every 3 can of Pumpkin, 1 can of green beans is used.

Now, the total number of John wants to use = 64

Let us assume the common factor in the ratio is m.

⇒ The number of Pumpkin can used = 3 m

The number of Green Beans can used = 1 m = m

So, the Total cans used = Number of (Pumpkin + Green Beans) can

⇒ 3 m + m = 64

or, 4 m = 64

⇒ m = 64/ 4 = 16

Hence, The number of Pumpkin can used = 3 m = 3 x 16 = 48 cans

The number of Green Beans can used = m = 16 cans

3 0

3 years ago

S<br>solve for X<br>2x - Px = 5

maxonik [38]

Answer:

$2x - P = 5 \\ x(2 - P) = 5 \\ \boxed{x = \frac{5}{(2 - P)} }$

5 0

3 years ago