Answer:
(10a+5)²= 100 a( a+1) + 25
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given
(10a+5)²
By using (a+b)² = a² +2ab +b²
= (10a)²+ 2 × 10a× 5 + (5)²
= 100a² + 100a + 25
= 100 a( a+1) + 25
Answer:
Table A represents a function, but Table B does not represent a function.
Step-by-step explanation:
We have to select the correct option among the given 4 options after judging the given two tables attached to this question.
The first table shows that for each x values there is only one y value. Therefore, this is a function.
But in the second table shows that for each x value there are multiple y values since we are getting y = 1 and 2 for x = 5.
Hence, table B is not a function. it is just a relation. (Answer)
Answer:
The pencil marks on your page show you exactly how to do that.
Step-by-step explanation:
Take advantage of two rules of exponents:
![\sqrt[n]{x}=x^{\frac{1}{n}}\\\\x^{-n}=\dfrac{1}{x^{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%5C%5C%5C%5Cx%5E%7B-n%7D%3D%5Cdfrac%7B1%7D%7Bx%5E%7Bn%7D%7D)
![(d)\quad x^{\frac{-1}{5}}=\dfrac{1}{x^{\frac{1}{5}}}=\dfrac{1}{\sqrt[5]{x}}\\\\(h)\quad x^{\frac{-2}{11}}=\dfrac{1}{x^{\frac{2}{11}}}=\dfrac{1}{\sqrt[11]{x^{2}}}](https://tex.z-dn.net/?f=%28d%29%5Cquad%20x%5E%7B%5Cfrac%7B-1%7D%7B5%7D%7D%3D%5Cdfrac%7B1%7D%7Bx%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%7D%3D%5Cdfrac%7B1%7D%7B%5Csqrt%5B5%5D%7Bx%7D%7D%5C%5C%5C%5C%28h%29%5Cquad%20x%5E%7B%5Cfrac%7B-2%7D%7B11%7D%7D%3D%5Cdfrac%7B1%7D%7Bx%5E%7B%5Cfrac%7B2%7D%7B11%7D%7D%7D%3D%5Cdfrac%7B1%7D%7B%5Csqrt%5B11%5D%7Bx%5E%7B2%7D%7D%7D)
5.34+6.89= 12 That is what I got
Answer: 1/250
Step-by-step explanation:
5^-3 × 2^-1
=> 1/5³ × 1/2
=> 1/125 × 1/2
=> 1/250
mark as brainly plss
