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Darina [25.2K]
3 years ago
5

A set of observations on a variable measured at successive points in time or over successive periods of time constitute aa. geom

etric series.
b. time invariant set.c. time series.

d. logarithmic series.
Mathematics
1 answer:
il63 [147K]3 years ago
6 0
You’re answer is B love!
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Frankie and Maria paid to get into the carnival, and they had to pay a certain amount per game. Frankie played 5 games and spent
Natali [406]

Answer:

It cost $8 per person to get into the carnival

Step-by-step explanation:

Let the entry cost be y

Let Cost of 1 game be x

Cost of 5 games = 5x

Cost of 12 games = 12x

Frankie played 5 games and spent $15.50 altogether.

So, 5x+y=15.50 --- A

Maria played 12 games and spent $26 altogether.

So, 12x+y=26 -- B

Plot the lines

5x+y=15.50 --- Black color

12x+y=26  --- Red color

Intersection point provides the solution

(x,y)=(1.5,8)

So, it cost $8 per person to get into the carnival

6 0
3 years ago
Whats 567 divided by 566789
Doss [256]

0.00100037227 will be your correct answer.

7 0
3 years ago
A line passes through the point (2, 10) and has a y-intercept of 4. What is the equation of the line? Help me please
joja [24]

Step-by-step explanation:

If it's a straight line the use formula

y = mx + c

m= gradient of line

c = y-intercept

we know that y-intercept is 4 so coordinate is

(0,4)

Equation also passes (2,10)

Use both coordinate to find gradient

m= vertical distance / horizontal distance

= (10-4) / (2-0)

= 3

y = 3x + 4

6 0
2 years ago
What is the median 18 16 -14 -15 8 18 7 11 17
Dominik [7]

Answer:

11

Step-by-step explanation:

-15, -15, 7, 8, 11, 16, 17, 18, 18

find the middle number after numbers are in order

hope this helps :)

8 0
3 years ago
Integral of 1/(x^2-x+1) ​
Lunna [17]

\boxed{\sf \displaystyle{\int}x^ndx=\dfrac{x^{n+1}}{n+1}}

\\ \sf\longmapsto \displaystyle{\int}\dfrac{1}{x^2-x+1}

\\ \sf\longmapsto \displaystyle{\int}x^{-2}-x^{-1}+1

\\ \sf\longmapsto \displaystyle{\int}x^{-2}-\displaystyle{\int}x^{-1}+\displaystyle{\int}1

\\ \sf\longmapsto \dfrac{x^{-2+1}}{-2+1}-\dfrac{x^{-1+1}}{-1+1}+1

\\ \sf\longmapsto \dfrac{x^{-1}}{-1}-\dfrac{x^0}{0}+1

\\ \sf\longmapsto -\dfrac{1}{x}-\dfrac{1}{0}+1

\\ \sf\longmapsto -\dfrac{1}{x}-\infty+1

\\ \sf\longmapsto \infty

6 0
3 years ago
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