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levacccp [35]
3 years ago
12

Which strategy is developed to pull together the various activities and competencies of each department so that corporate and bu

siness unit performance improves and resource productivity is maximized?
A) business strategy
B) competitive strategy
C) generic strategy
D) enterprise strategy
E) functional strategy
Business
1 answer:
Alik [6]3 years ago
4 0

Answer: E) functional strategy

Explanation:Functional strategies are operational strategies. They are short-term goal-directed decisions and actions of the organization's various functional areas.

The role of functional strategy is to work together to achieve business and corporate strategies. They are where competitive and corporate strategies get implemented.

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Which of the following is a unique feature of credit unions?
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D) Both A & B
<span>a)Credit unions are typically owned and run by their members
</span><span>b)Credit unions limit membership to certain people or groups</span>
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When external benefits are significant: market output is too high. market output is too low. market output is at the efficient l
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<span>External benefits are more significant when market output at the efficient level. So if anyone ignores the external benefits and only focuses on private benefits, this may lead to market quantity getting low and also the social surplus might get to its minimum.</span>
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Suppose there are only three people in the economy: jane, harry, and bob. the individual demand for corn for each of these consu
OleMash [197]

Answer:

$25

Explanation:

Please check the attached image for a diagram of exhibit 3-1

The total quantity demanded can be found by adding the sum of the quantity demanded at $5.

Jane doesn't demand at $5, so her quantity demanded is 0

For Henry it is 8

For Bob, it is 17

Total quantity demanded ia 25

I hope my answer helps you

8 0
3 years ago
What is productivity?
REY [17]

Answer:

is the process in which an item or good is bringing profit to a business

Explanation:

6 0
3 years ago
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The Internal Revenue Service (IRS) provides a toll-free help line for taxpayers to call in and get answers to questions as they
kondor19780726 [428]

Complete question is;

The Internal Revenue Service (IRS) provides a toll-free help line for taxpayers to call in and get answers to questions as they prepare their tax returns. In recent years, the IRS has been inundated with taxpayer calls and has redesigned its phone service as well as posting answers to frequently asked questions on its website (The Cincinnati Enquirer, January 7, 2010). According to a report by a taxpayer advocate, callers using the new system can expect to wait on hold for an unreasonably long time of 14 minutes before being able to talk to an IRS employee. Suppose you select a sample of 50 callers after the new phone service has been implemented; the sample results show a mean waiting time of 12 minutes before an IRS employee comes on line. Based upon data from past years, you decide it is reasonable to assume that the standard deviation of waiting times is 10 minutes. Use a = 0.05.

a. State the hypotheses.

b. What is the p-value (to 4 decimals)?

c. Using a = 0.05, can you conclude that the actual mean waiting time is significantly less than the claim of 14 minutes made by the taxpayer advocate

Answer:

A) Null hypothesis; H0: μ ≥ 14

Alternative hypothesis; Ha: μ < 14

B) P-value ≈ 0.0793

C) The p-value is less than the significance value and thus we will fail to reject the null hypothesis and conclude that the evidence is not sufficient to reject the claim that the actual mean waiting time is significantly less than the claim of 14 minutes made by the taxpayer advocate

Explanation:

We are given;

Population mean time; μ = 14

Sample mean time; x¯ = 12

Population size; n = 50

Standard deviation; σ = 10

A) Let's state the hypotheses;

Null hypothesis; H0: μ ≥ 14

Alternative hypothesis; Ha: μ < 14

B) Let's first find the test statistic from the formula;

z = (x¯ - μ)/(σ/√n)

z = (12 - 14)/(10/√50)

z = -1.41

From online p-value from z-score calculator attached using; z = -1.41: α = 0.05 and one tailed hypothesis, we have;

P-value ≈ 0.0793

C) The p-value is less than the significance value and thus we will fail to reject the null hypothesis and conclude that the evidence is not sufficient to reject the claim that the actual mean waiting time is significantly less than the claim of 14 minutes made by the taxpayer advocate

8 0
3 years ago
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