Answer:
<h2><u>since </u><u>DE≅EF</u></h2>
<u>CD=</u><u>CF </u><u>(</u><u>cpct)</u>
<u>
</u>
<h2><u>hope</u><u> it</u><u> helps</u><u> you</u><u><</u><u>3</u></h2>
It should me b I don’t know if it is but it should be
Answer:
Step-by-step explanation:
Given that X - the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a standard deviation of 2.7 inches.
Height of male pilot = 74.2 inches
We have to find the percentile
X = 74.2
Corresponding Z score = 74.2-72.6 = 1.6
P(X<174.2) = P(Z<1.6) = 0.5-0.4452=0.0548=5.48%
i.e. only 5% are below him in height.
Thus the malepilot is in 5th percentile.
The answer is 6.1 = 6 1/10