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sdas [7]
2 years ago
14

The X- and y-coordinates of point P are each to be chosen at random from the set of integers 1 through 10.

Mathematics
1 answer:
bagirrra123 [75]2 years ago
3 0

Answer:

Ok, as i understand it:

for a point P = (x, y)

The values of x and y can be randomly chosen from the set {1, 2, ..., 10}

We want to find the probability that the point P lies on the second quadrant:

First, what type of points are located in the second quadrant?

We should have a value negative for x, and positive for y.

But in our set;  {1, 2, ..., 10}, we have only positive values.

So x can not be negative, this means that the point can never be on the second quadrant.

So the probability is 0.

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