What are the new vertices of triangle QRS, shown, if the triangle is reflected across the line y = x, also shown? Question 6 opt
ions: A) Q′ = (–2,–3), R′ = (1,1), S′ = (2,–1) B) Q′ = (2,–4), R′ = (4,0), S′ = (3,–1) C) Q′ = (2,–5), R′ = (5,0), S′ = (2,–1) D) Q′ = (5,2), R′ = (0,5), S′ = (1,2)
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The equation to derive the distance d is . The lengths of the other legs of the given triangle are (y2 - y1) and (x2 - x1).
Consider the two points (x1, y1) and (x2, y2)
The formula used for calculating the distance between the two points is
distance =
Given that,
The triangle in the graph has vertices (x1, y1), (x2, y2), and (x2, y1)
Since this triangle makes 90°, it is a right-angled triangle.
Hypotenuse = (x1, y1) to (x2, y2), Adjacent = (x1, y1) to (x2,y1), and Opposite = (x2, y1) to (x2, y2).
Consider the length of the hypotenuse = d
So, using the distance formula, the length of the hypotenuse(d) is,
And the lengths of the other two legs of the given triangle are,
Length of the adjacent side: (x1, y1) to (x2,y1)
=
=
=
Length of the opposite side: (x2, y1) to (x2, y2)
=
=
=
Therefore, the derived distances for the given triangle are:
, (x2 - x1), and (y2 - y1).
Learn more about the distance between two points here:
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