A circle is centered at 7,8 and has a radius of 11 what is the equation?

Mathematics

2 answers:

denis-greek [22]2 years ago

7 0

SchwarzschildRadius here:

So,

The equation for a circle is:

$(x-h)^2+(y-k)^2=r^2$

Where the center of the circle is (h,k), and the radius of the circle is r.

Substituting 7,8 for (h,k) and 11 for r in the equation gives us:

$(x-7)^2+(y-8)^2=11^2$

That would be standard form.

Hope this helps!

Free_Kalibri [48]2 years ago

3 0

Answer:

(x − 7)2 + (y − 8)2 = 121

Step-by-step explanation:

I took the quiz and this was the correct answer. Although (x − 7)2 + (y − 8)2 = 11 was an answer choice it was incorrect. Here is proof from my quiz for verification.

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the size of the second application is 3.45 MB less than he first application. What is the size of the second application

mr_godi [17]

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<h3>Equation</h3>

Let

Size of the first application = x

Size of the second application= x - 3.45 mb

For instance,

if the size of the first application is 297 MB

Size of the second application= x - 3.45 mb

= 297 MB - 3.45 MB

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1 year ago

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erik [133]

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