Answer:
The confidence interval at this level of confidence is between 5.4455 and 12.3545.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find M as such

In which s is the standard deviation of the sample, which is also called standard error. So

The lower end of the interval is the sample mean subtracted by M. So it is 8.9 - 3.4545 = 5.4455
The upper end of the interval is the sample mean added to M. So it is 8.9 + 3.4545 = 12.3545
The confidence interval at this level of confidence is between 5.4455 and 12.3545.
FORMULA:
- Volume of hemisphere = 2/3πr³
ANSWER:
We are given a hemisphere of radius 3.1inches.
So, Volume = 2/3 × 3.14 × (3.1)³
- 187.08/3
- 62.36in³ or 62.4in³ rounded.
The proportion is 0.4401.
We find z-scores that correspond with both ends of this interval. Z-scores are given using the formula:

For the lower end,

The proportion of scores to the left of this number is 0.2514.
For the higher end, the z-score is

The proportion of scores to the left of this number is 0.6915.
To find just the proportion of scores between these two, we subtract;
0.6915-0.2514 = 0.4401.
Answer:
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