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zysi [14]
3 years ago
6

EASY POINTS! (50)

Mathematics
2 answers:
umka2103 [35]3 years ago
7 0

Answer:

1/2(7)(4) + 6(5) = 44

1/2*64+3(7) = 53

12(6)+14*4 = 128

You are welcome

Step-by-step explanation:

statuscvo [17]3 years ago
7 0

Answer:

1/2(7)(4)+6(5)=44

1/2⋅64+3(7)= 53

12(6)+14=86

Step-by-step explanation:

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A large chocolate bunny costs $2.07. Chris only has $1.12. How much more money does Chris need in order to buy the bunny?
Reptile [31]

Answer

0.95 more cents

Step-by-step explanation:

2.07-1.12=0.95

8 0
2 years ago
Sam sharpens pencils for his after school job. He can sharpen 26 pencils in 6 minutes. If he keeps this rate, how many pencils c
andrey2020 [161]

Answer:

234

Step-by-step explanation:

multiply 26 x 9

8 0
3 years ago
Find the measure of and angle between o degrees and 360 degrees coterminal with an angle of 399 degrees in standard position
horrorfan [7]

Answer:

39 degrees.

Step-by-step explanation:

We want an angle  x  such that   0 < x < 360   and angle x is coterminal with an angle of measure 399 degrees.

so   x =  399 - 360 = 39 degrees

5 0
3 years ago
What is the slope of the line y= 3?
Kipish [7]

Answer:

Undefined

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck
Nimfa-mama [501]
\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}
\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}

Now, isolate the variables, so you can integrate.
(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}
\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}
2y - \frac{y^{2}}{2} = sin^{-1}\frac{x}{\sqrt{2}} + \frac{1}{2}C


4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C
y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C
(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C
(y - 2)^{2} = 4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C


y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}
y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}

At x = 1, y = 0.
0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}
-2 = \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}

4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C > 0
\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}


4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C
0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C
C = -2sin^{-1}\frac{1}{\sqrt{2}} = -2\frac{\pi}{4}
C = -\frac{\pi}{2}

\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}
6 0
3 years ago
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