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3 years ago

What is the solution to the following system of linear equations?

1 answer:

8 0

x − 2y = −1 => x = 2y -1

2x + y = −12
2(2y - 1) + y = -12
4y - 2 + y = -12
5y = -10
y = -2
x = 2·(-2) - 1
x = -4 - 1
x = -5

Answer D (-5,-2)

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If the door to the library is at (2, 4), the door to the mall is at (8, 2), and one

guapka [62]

Answer:

6 miles

Step-by-step explanation:

The distance formula is expressed as;

D = √(x2-x1)²+(y2-y1)²

D = √(2-4)²+(8-2)²

D = √(-2)²+(6)²

D = √4 + 36

AD = √40

AD = 6.32

Hence the approximate distance between the library and the mall is 6 miles

5 0

3 years ago

Write a number of grams between 10 and 20, and then write an equivalent amount in milligrams.

oksano4ka [1.4K]

Answer:

15 grams and 15000 milligrams

Step-by-step explanation:

3 0

3 years ago

А Campus athletics is interested in the proportion of registered students living on campus who play basketball recreationally du

r-ruslan [8.4K]

Answer:

c. We are 95% confident that, among the population of students that play basketball recreationally, the proportion who live on campus is between 0.12 and 0.18.

Step-by-step explanation:

According to the question, it is mentioned that there is 95% confidence interval and it is calculated (0.12,0.18)

So the correct interpretation is that they are 95% confident that the students who play basketballs the proportion should lies between 0.12 and 0.12

So, the option C is correct

The rest of the options are wrong

3 0

3 years ago

Vertical angles are supplementary, true or false?

beks73 [17]

Answer:

False

Step-by-step explanation:

Vertical angles are a pair of opposite angles created by intersecting lines. The Vertical Angles Theorem states that if two angles are vertical, then they are congruent.

4 0

3 years ago

Read 2 more answers

4a/3-b/4=6 5a/6+b=13 Solve linear system by elimination

kondor19780726 [428]

$\bf \cfrac{4a}{3}-\cfrac{b}{4}=6
\qquad \qquad 
\cfrac{5a}{6}+b=13
\\\\\\
\textit{let us remove the denominators off those folks}\\
\textit{by multiplying the first one by 12, both sides}\\
\textit{and the second one by 6, both sides, thus}
\\\\\\
12\left( \cfrac{4a}{3}-\cfrac{b}{4} \right)=12(6)\implies 16a-4b=72
\\\\\\
6\left( \cfrac{5a}{6}+b \right)=6(13)\implies 5a+6b=78$

$\bf \textit{now, let's do the elimination}
\\\\

\begin{array}{llll}
16a-4b=72&\boxed{\times 3}\implies &48a-\underline{12b}=216\\\\
5a+6b=78&\boxed{\times 2}\implies &10a+\underline{12b}=156\\
&&--------\\
&&58a+0\quad=372
\end{array}$

solve for "a", once you get "a", plug it back into either equation to get "b"

3 0

3 years ago