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3 years ago

Factorise completely 2y^2-4y

2 answers:

8 0

To factor an expression, first you have to find the GCF or Greatest Common Factor of all of the pieces of the expression.

The GCF of 2y^2 and -4y is 2y

So, to factor this expression, we need to divide all of the pieces of the expression by the GCF.

2y(y-2)

2y^2 - 4y in completely factored form is 2y(y-2)

bekas [8.4K]3 years ago

6 0

You find the gcf which is 2y
you factor it out: 2y(y-2)

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What expression is equal to (3x^2yz) (5xy^3z^2)

Svetlanka [38]

Your Answer is <span>15x^3y^4z^3</span>

8 0

3 years ago

$149 MP3 player 40% discount

MatroZZZ [7]

40% of 149 is 59.60

149-59.60= 89.40

5 0

3 years ago

What is the radius of a circle with a central angle of 4π7 radians that intercepts an arc of length 12π inches?

SCORPION-xisa [38]

Radian measure is given by dividing the length of an arc by the radius of a given circle. Such that an arc that subtends an angle of 1 radian to the center of a circle is equivalent to the radius of the circle.
Therefore; θ = s/r where θ is the angle subtended in radians, s is the length of the arc and r is the radius of the circle.
Hence; r = s/θ
= 12π ÷ (4π/7)
= 12 × (7/4)
= 21 inches

3 0

3 years ago

If JK and LM are congruent and parallel, then JKL and MLK are congruent.<br> True<br> False

Alex787 [66]

Answer:

TRUE

Step-by-step explanation:

Given that line segment JK and LM are parallel. From picture we see that LK is transversal line.

We know that corresponding angles formed by transversal line are congruent.

Hence ∠JKL = ∠ MLK ...(i)

Now consider triangles JKL and MLK

JK = LM {Given}

∠JKL = ∠ MLK { Using (i) }

KL = KL {common sides}

Hence by SAS property of congruency of triangles, ΔJKL and ΔMLK are congurent.

Hence given statement is TRUE.

5 0

3 years ago

if $4000 is invested in an account that pays interest compounded continuously, how long will it take to grow to $8000 at 7%?

Archy [21]

So, since it is continuously, we need to think of PERT

$A=P\times e^{rt}$

So, we just plug our numbers in to solve for T

$8000=4000e^{.07t}\\\ln(8000)=\ln(4000e^{.07t})\\\ln(8000) = \ln(4000) + \ln(e^{.07t})\\\ln(8000)=\ln(4000)+.07t\ln(e)\\\ln(8000)=\ln(4000)+.07t\\\frac{\ln(8000)}{\ln(4000)}=.07t\\\frac{\ln(8000)}{.07\ln(4000)}=t\\ 15.479=t$

It will take 15.479 years

7 0

3 years ago