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3 years ago

If 9 to the power of x = 27, what is x. Method as well plz!

Mathematics

2 answers:

Alexandra [31]3 years ago

5 0

You can use logarithms:

Log9(27) which will give you the value of x

X= 1.5

e-lub [12.9K]3 years ago

3 0

$9^x=27\\\\(3^2)^x=3^3\\\\3^{2\cdot x}=3^3\\\\3^{2x}=3^3\iff 2x=3\ \ \ /:2\Rightarrow x=1.5$

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ki77a [65]

Answer:

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Step-by-step explanation:

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3 years ago

How do you simplify that question? For algebra 1.

motikmotik

$\left( \sqrt{x^{-3}} \right)^5 = \left( \sqrt{ \frac{1}{x^3} } \right)^5= \frac{1}{ (\sqrt{x^3})^5 } = \frac{1}{ \sqrt{x^{15}} } = \frac{1}{x^7 \sqrt{x} }$

<span>Explanation for the last step:</span>
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3 years ago

Use the change of base formula to evaluate log3(73).

Marrrta [24]

The change of base formula allows you to write a logarithm in terms of logarithms with another base. It follows this pattern,

$log_{a}x = \frac{ log_{b}x }{log_{b}a }$

where a≠1 and b≠1

Assigning the base to be 7,

$log_{3}73 = \frac{ log_{7}73 }{log_{7}3 }=3.9$

I hope I was able to answer your question. Have a good day.

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3 years ago

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WINSTONCH [101]

Answer:

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Step-by-step explanation:

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