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antoniya [11.8K]
2 years ago
13

Round to the nearest hundreds place.

Mathematics
2 answers:
Sphinxa [80]2 years ago
7 0

Answer:

300 kids

Step-by-step explanation:

Svetlanka [38]2 years ago
3 0

nearest hundred place : 300

hope this helps

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Pls answer 4 and 5 for brainly
seropon [69]

Number 4 would be: C

And number 5 would be: C

Please Mark as Brainliest!!!

6 0
3 years ago
Read 2 more answers
Solve for x -9<4x+3<27 enter your answer as one inequality in the box
ludmilkaskok [199]

If a< c< b then a<c and c<b

Separate the equation into 2 separate ones and solve them:

X-9 < 4x +3

Subtract 3 from both sides:

X-12 < 4x

Subtract x from both sides:

-12< 3x

Divide both sides by 3:

X > -4

4x+3 < 27

Subtract 3 from both sides

4x < 24

Divide both sides by 4

X <6

Combine to get one inequality:

-4<x<6

6 0
3 years ago
Does anyone know how to do this? And can you also help me with this problem, thank you :)
GenaCL600 [577]
<span>Multiply equation(2) with 4 so that coefficient of become same in both the equations(You can make coefficient of y same and can follow the following procedure.) 
</span><span>* Subtract (3) from (1) 
* </span>Divide both sides by -19
*Subtract 21 from both sides.
*Divide both sides by 4
so the solution is     x= 3 and  y= -7
Hope I helped you :)
6 0
3 years ago
What is the value of x?​
masya89 [10]

Answer:

Option D is correct.

Step-by-step explanation:

We can tell that

  • 4x + \frac{x}{2} + 2 + \frac{3x-4}{2} = 180

Now, let's simplify.

=> 4x + 2 + \frac{4x-4}{2} = 180

=> 4x + 2 + 2x-2 = 180

=> 4x + 2x = 180

=> 6x = 180

=> x = 30

Therefore, Option D is correct.

Hoped this helped.

5 0
2 years ago
Write the slope-intercept form of an equation of the line that passes through the given point and is parallel to the graph of ea
koban [17]

Answer:

slope(m)=5/4 and

y-intercept (c)=12

Step-by-step explanation:

here,given equation of a line is

5x-4y-1=0...eqn(i)

equation of any line parallel to line(i) is

5x-4y+k=0...eqn(ii)

since,the line(ii) passes through (-8,2)[replacing x=-8 and y=2 in eqn(ii), we get]

5*(-8)-4*2+k=0

or-40-8+k=0

•°•k=48

substituting the value of k=48 in eqn(ii),

5x-4y+48=0 is the required equation of the line.

now,

changing eqn(ii) in slope intercept form we get,

4y=5x+48

or,y=5x/4+48/4

or,y=(5/4)x+12

comparing it into y=mx+c we get,

slope(m)=5/4 and y-intercept(c)=12

6 0
3 years ago
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