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2 years ago

Explain your work !!!! What is 17^3 A. 20 B. 4913 C. 51 D. 306

Mathematics

2 answers:

schepotkina [342]2 years ago

8 0

Answer:

B. 4913

Step-by-step explanation:

17^3 bassically means 17x17x17

So 17x17x17 is 4913

Travka [436]2 years ago

4 0

A number raised to an exponent is that number multiplied by itself that number of times.

17^3 = 17 x 17 x 17 = 4913

The answer is B.

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Cual es el minimo comu multiplo de 81,27,9

Brums [2.3K]

La respuesta es 81.

Eso es porque
81*1= 81,
27*3=81,
y 9*9=81.

8 0

3 years ago

Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the p

PIT_PIT [208]

Answer:

Colin has 8 sheets left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = $x$

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

$\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)$

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

$\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)$

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

$\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8$

So, the answer is:

Colin has 8 sheets left for his third class.

5 0

3 years ago

the area of a rectangle garden is 38 1/4 square meters.The width of the garden is 4 1/2 meters.Find the length of the garden.

never [62]

Area = 38 1/4 = 153/4

Width = 4 1/2 = 9/2

Area = Length x Width

Length = Area/Width

So divide both of them:
$\sf{ \frac{153}{4} \div \frac{9}{2} =\sf{ \frac{153}{4} \times \frac{2}{9} = \frac{9 \times 17}{2\times 2}\times \frac{2}{9} = \frac{17}{2}$

So the length is equal to $\boxed{\sf{\frac{17}{2}}}$

4 0

2 years ago

Whats the y intercept y=.25x + .30

BigorU [14]

the Y intercept is .30

5 0

2 years ago

A solar collector is 2,0 m long by 1,5 m wide. It is held in place

icang [17]

Answer:

The width of the frame is 0.0746 meters

Step-by-step explanation:

We are told that after the frame has been attached to the solar collector, the area that is left exposed is $2.5m^2$ . As we see in the figure, the dimensions of this area are

$(w-2x)$ and $(l-2x)$

where $x$ is the width of the frame.

The product of these dimensions must equal the exposed area:

$(w-2x)(l-2x)=2.5m^2$

Now since $w=1.5m$ and $l=2m$ we have:

$(1.5-2x)(2-2x)=2.5$

we expand this and solve for x using the quadratic formula:

$4x^2-7x+3=2.5$

$4x^2-7x+0.5=0$

we get two solutions:

$x=1.6753$

$x=0.0746$

We take the second solution i.e $x=0.0746$ , because first one gives a width larger than the dimensions of the solar collector which cannot be possible.

Thus the width of the frame is 0.0746 meters.

7 0

3 years ago