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SOVA2 [1]
3 years ago
6

Ultraviolet radiation and radiation of shorter wavelengths can damage biological molecules because they carry enough energy to b

reak bonds within the molecules. A carbon-carbon bond requires 348 kJ/mol to break.
What is the longest wavelength of radiation with enough energy to break carbon-carbon bonds?
Chemistry
1 answer:
DIA [1.3K]3 years ago
5 0
<h3>Answer:</h3>

Longest wavelength = 343.7 nm

<h3>Solution and Explanation:</h3>

In this question we need to first use the concept of energy of a photon.

Energy of a photon, E, is given by the formula, E = hf, where h is the plank's constant, f is the frequency.

But since, f is given by dividing speed, c, by wavelength, λ, then;

E = hc/λ

We are given 348 kJ/mol required to break carbon-carbon bonds.

We know that; 1 mole of bonds = 6.022 × 10^23 bonds.

We are required to find the longest wavelength with enough energy to break the C-C bonds.

This can be worked out in simple steps:

Step 1:  Energy required to break one bond (kJ/bond)

1 mole of bonds = 6.022 × 10^23 bonds.

Therefore;

348 kJ = 6.022 × 10^23 bonds.

Thus;

1 bond = 348 kJ ÷ 6.022 × 10^23 bonds.

           =  5.778 x 10^-22 kJ

But; 1000 joules = 1 kJ

Hence; energy per bond =  5.778 x 10^-19 Joules

Step 2: Energy per photon

Breaking one bond requires energy equivalent to energy of a photon.

Therefore;

1 photon = 5.778 x 10^-19 Joules

              = 5.778 x 10^-19 J/photon

Step 3: Calculating the wavelength

From the equation of energy of a photon;

E = hc/λ

h is the plank's constant = 6.626 × 10^-34 J/s

c is the speed of light in vacuum = 2.9998 × 10^8 m/s

E is the energy of a photon =  5.778 x 10^-19 Joules

Therefore, making λ (wavelength) the subject;

wavelength = \frac{hc}{E}

= \frac{(6.626 . 10^{-34})(92.9998.10^8) }{(5.778 .10^{-19} )}

= 3.437. 10^{-7} m

       = 3.437 x 10^-7 m

But; 1 nm = 10^-9 m

Thus;

wavelength = 343.7 nm

Therefore, the longest wavelength of the radiation will be 343.7 nm

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Was the acetylacetone miscible with water? What about if NH3 is added to the solution? Why?
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Answer:

See explanation

Explanation:

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However the introduction of ammonia, leads to the ionization of the specie. In the presence of a base(such as NH3), the molecule acetylacetone is deprotonated and its corresponding anion is formed. This anion can now interact with water and become miscible with it.

4 0
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During a laboratory experiment you discover that an enzyme-catalyzed reaction has a delta G of -20 kcal/mol. If you double the a
Ilia_Sergeevich [38]

Answer:

-20 kcal/mol

Explanation:

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Note that from the relation above, enzyme is not a factor nor is activation energy a factor.

3 0
3 years ago
Which are the four quantum numbers of the last potassium layer?
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8 0
3 years ago
Suppose a 250 ml flask is filled with 1.3mol of O2 and 1.5 mol of NO. The following reaction becomes possible: The equilibrium c
bonufazy [111]

<u>Answer:</u> The equilibrium molarity of oxygen gas is 7.1 M

<u>Explanation:</u>

We are given:

Moles of oxygen gas = 1.3 mole

Moles of NO = 1.5 moles

Volume of the flask = 250 mL = 0.250 L   (Conversion factor:  1 L = 1000 mL)

To calculate the molarity, we use the equation:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume of solution (in L)}}

Molarity of oxygen gas = \frac{1.3}{0.25}=5.2M

Molarity of NO = \frac{1.5}{0.25}=6.0M

The chemical equation follows:

                              O_2+N_2\rightleftharpoons 2NO

Initial:                  5.2    -           6.0

At eqllm:          5.2+x     +x      6.0-2x

The expression of K_c for above equation follows:

K_c=\frac{[NO]}{[O_2][N_2]}

K_c=0.394   (Assuming)

Putting values in above equation, we get:

0.394=\frac{(6.0-2x)^2}{(5.2+x)\times x}\\\\-3.606x^2+26.0488x-36=0\\\\x=1.9,5.4

Neglecting the value of x = 5.4 because this cannot be greater than the initial value.

Concentration of oxygen gas at equilibrium = (5.2 + x) = 5.2 + 1.9 = 7.1 M

Hence, the equilibrium molarity of oxygen gas is 7.1 M

8 0
3 years ago
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