(11.21 g BaSO4) / (233.4 g/mol BaSO4) = 0.0480 mol BaSO4 and original barium salt
<span>(10.0 g) / (0.0480 mol) = 208.3 g/mol </span>
<span>So it must have been BaCl2.
I think it letter A.
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
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Answer:
True.
Explanation:
The mass number of an atom can be calculated using no of protons and the no of neutrons.
Mass number = no of protons + no of neutrons
We can rearrange the above formula to find the no of neutrons as follows :
no of neutrons = Mass number - no of protons
or
Neutrons = Mass - protons.
Hence, the given statement is true.
Answer:
32.4 K
Explanation:
From the given parameters;
Initial pressure P1= 50.0 mmHg
Initial temperature T1= 540K
Final Temperature T2 = ?????
Final pressure P2=3 mmHg
Now using this relationship;
P1/T1 = P2/T2
We have; P1T2= P2T1
Hence;
T2= P2T1/P1
T2= 3 ×540/50.0
T2= 32.4 K
Answer:
1837.89 Lt
Explanation:
The chemical reaction for this situation is:
NaHCO₃ + HCl → NaCL + H₂O + CO₂ ₍g₎
Where the mola mass we need are:
M NaHCO₃ = 84 g/mol
M CO₂ = 44 g/mol
As we have 6.00 Kg of sodium bicarbonate, then:
6 Kg NaHCO₃ = 71.43 moles of NaHCO₃
Due the stoichiometry of this chemaicl reaction:
1 mol NaHCO₃ = 1 mol CO₂
71.43 moles NaHCO₃ = 71.43 moles CO₂
And considering that CO₂ is an ideal gas, we can use the following formula:
PV=nRT
V = (nRT)/P
n = 71.43 mol
R = 0.083 Ltxatm(molxK)
T = 37°C = 310 K
P = 1 atm
So: V = (71.43x0.083x310)/1
V CO₂ = 1837.89 Lt
You are given the neutralization of acetic acid with sodium hydroxide. Also, you are given the k for acetic acid, which is 1.8 x 10⁻⁵. You are asked to find the<span> approximate value of the equilibrium constant, kn, for the neutralization. We will have a reaction of both acetic acid and sodium hydroxide.
CH</span>₃COOH + NaOH → CH₃COONa + H₂O
which comes from
CH₃COOH → CH₃COO⁻ + H⁺
H⁺ + OH⁻ → H₂O<span>
</span>The k for water is always 1.0 x 10¹⁴. The Ksp for the reaction will be
<span>
Ksp = [</span>CH₃COOH][H₂O]
Ksp = (1.8 x 10⁻⁵)(1.0 x 10¹⁴)
<span>Ksp = 1.8 x 10</span>⁹
