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3 years ago

In the diagram, point O is the center of the circle and m∠ADB = 43°. If m∠AOB = m∠BOC, what is m∠BDC?

Mathematics

2 answers:

mr_godi [17]3 years ago

8 0

Answer:

B. 43

Step-by-step explanation:

I just took the test on plato :)

Sladkaya [172]3 years ago

7 0

Answer:

m∠BDC = 43°

Step-by-step explanation:

According to the theorem every peripheral angle in the circle is equal to half value of central angle.

Angle m∠ADB is corresponding peripheral angle of central angle m∠AOB.

According to this m∠AOB = 2· m∠ADB = 2· 43 = 86°

If angle m∠BOC=m∠AOB= 86°

Angle m∠BDC is corresponding peripheral angle of central angle m∠BOC

According to this m∠BDC = m∠BOC/2 = 43°

Good luck!!!

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gayaneshka [121]

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