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Paha777 [63]
3 years ago
7

a coin operated machine sells plastic rings . it contains 6 yellow rings,11 blue rings,15 green rings,and 3 black rings.sarah pu

ts a coin into the machine. find the theoretical probabilty the sarah gets a black ring, rounded to the nearest thousandth.
Mathematics
1 answer:
Mariana [72]3 years ago
5 0
Sample space ={6y+11b+15g+3bk} = 35 elements
number of black rings=3
probability (black ring) =3/35=0.085
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Of the cars sold during the month of July, 89 had air conditioning, 99 had an automatic transmission, and 74 had power steering.
DedPeter [7]

Answer:

There are a total of 23 cars with air conditioning and automatic transmission but not power steering

Step-by-step explanation:

Let A be the cars that have Air conditioning, B the cars that have Automatic transmission and C the cars that have pwoer Steering. Lets denote |D| the cardinality of a set D.

Remember that for 2 sets E and F, we have that

|E \cup F| = |E| + |F| - |E \cap F|

Also,

|E| = |E ∩F| + |E∩F^c|

We now alredy the following:

|A| = 89

|B| = 99

|C| = 74

|A \cap B \cap C| = 5

|(A \cup B \cup C)^c| = 24

|A \ (B U C)| = 24 (This is A minus B and C, in other words, cars that only have Air conditioning).

|B \ (AUC)| = 65

|C \ (AUB)| = 26

|B \cap C| = 11

We want to know |(A∩B) \ C|. Lets calculate it by taking the information given and deducting more things

For example:

99 = |B| = |B ∩ C| + |B∩C^c| = 11 + |B∩C^c|

Therefore, |B∩C^c| = 99-11 = 88

And |A ∩ B ∩ C^c| = |B∩C^c| - |B∩C^c∩A^c| = |B∩C^c| - |B \ (AUC)| = 88-65 = 23.

This means that the amount of cars that have both transmission and air conditioning but now power steering is 23.

3 0
3 years ago
Marcos had 15 coins in nickels and quarters. He had 3 more quarters than nickels. He wrote a system of equations to represent th
hodyreva [135]

Answer:

There are 6 coins in nickels and 9 coins in quarters.

Step-by-step explanation:

Now, to find the solution.

According to question:

The number of nickels = x.

The number of quarters = y.

So, the total number of coins:

x+y=15.

He had 3 more quarters than nickels.

Thus,

y=x+3 .....(1)

Now, to get the solution:

x+y=15

Substituting the equation (1):

x+(x+3)=15

x+x+3=15

2x+3=15

<em>Subtracting both sides by 3 we get:</em>

<em />2x=12<em />

<em>Dividing both sides by 2 we get:</em>

x=6.

<em>The number of nickels = 6.</em>

Now, substituting the value of x in equation (1):

y=x+3\\\\y=6+3\\\\y=9.

<em>The number of quarters = 9.</em>

Thus, there are 6 coins in nickels and 9 coins in quarters.

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

I hope this helps.

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